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I'm currently taking classes on General Relativity, and whilst working on Geodesis equation:

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Find out that for mass particle q is equivalent to proper time but in case of photon the proper time of photon is zero. Could you please explain why? (For note, surprisingly but i didn't have proper Special relativity lessons)

Qmechanic
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1 Answers1

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Because for a massless particle $ds^2=0$.

Oбжорoв
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