In fusion, why are nucleons of the product nucleus tightly bound and in a lower energy configuration than the nucleons in the reactant nuclei? I think the reason a large amount of energy is released is due to the nucleons of the product nucleus being in a lower energy state as compared to the nucleons of the reactant nuclei... Is this theory correct? Please clarify this doubt with as much detail as possible.... :(
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Yes , it is the release of energy, https://en.wikipedia.org/wiki/Nuclear_fusion#Process see – anna v Jun 12 '22 at 10:48
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But that energy release is due to what? – fusion researcher Jun 12 '22 at 15:05
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In all of physics observations ( from thermodynamics to quantum) if there is a possible lower energy state where conservation laws are obeyed, systems go to the lowest energy states, and this is in all the models describing the data. – anna v Jun 12 '22 at 15:34
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But the reason for energy release? – fusion researcher Jun 13 '22 at 09:37
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https://physics.stackexchange.com/questions/87371/why-a-system-should-be-at-its-lowest-energy-state-for-its-stability https://physics.stackexchange.com/questions/64146/the-preference-for-low-energy-states – anna v Jun 13 '22 at 09:57
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I know that these systems have a lower energy state but how does this cause an energy release? – fusion researcher Jun 13 '22 at 10:02
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from conservation of energy for the total system. It is a law, i.e. it comes from observations of data and has not been falsified up to now. – anna v Jun 13 '22 at 10:23