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Why does the spectrum for Bremsstrahlung radiation decrease linearly with photon energy after a certain point (50 keV in the plot)?

Plot of X-rays

probablysid
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    the article that has the plot you show also discusses how it emerges , in a complicated manner as far as the dependence of variables https://physicsopenlab.org/2017/08/02/bremsstrahlung-radiation/ – anna v Jan 15 '23 at 05:17
  • I used brem in my PhD experiment, $d(\gamma, p)n$, and I do not recall a linear decrease. – JEB Jan 15 '23 at 05:42
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    @annav Doesn't that formula explain how the kinetic energy of the incident electrons is lost/converted into Bremsstrahlung radiation, rather than explaining why there is a maximum photon energy, and why X-ray intensity profile decreases linearly with photon energy? – probablysid Jan 15 '23 at 12:42
  • If you look at the lot of experimental figures, it is a qualitative plot, not a solution of the formula – anna v Jan 15 '23 at 14:30
  • The E in the formula is the energy of the radiating particle. – anna v Jan 15 '23 at 14:39
  • here is a plot of photon energies for different E https://www.researchgate.net/figure/Plot-of-bremsstrahlung-spectrum-for-end-pint-energies-of-12-14-16-45-50-55-60-and_fig3_257989624 – anna v Jan 15 '23 at 14:42
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    This gives the Kramer formula which is what you are asking about https://folk.ntnu.no/floban/KJ%20%203055/X%20%20Ray/Bremsstrahlung.htm , also https://en.wikipedia.org/wiki/Kramers%27_law – anna v Jan 15 '23 at 14:54

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