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So imagine we are doing kinetic gas theory with spheres. To model the collisions however, we consider the potential used over here.

We choose the regularized potential as

$$ V_{\varepsilon}~=~\frac{(x_1-x_2)^2}{\varepsilon}\theta(|x_1 - x_2| - d).$$

where $V_{\varepsilon}$ is a family potentials of ${\varepsilon}$ as a label, $x_1$ is the position of the first gas molecule, $x_2$ is the position of the second gas molecule and $d$ is the diameter of our molecules.

A general observation for our potential is while $\epsilon \to 0^+$ the time spent in the potential $t \to 0$. We, presume the time spent $\tau_C$ in the potential is small but not $0$ and we realise if we vary the steep slope of our short ranged potential then it should not affect the equation of state. Thus, if we have a time averaged force:

$$ \frac{\partial \langle F \rangle_t}{\partial \rho} = \frac{\partial \langle F \rangle_t}{\partial T} = \frac{\partial \langle F \rangle_t}{\partial P} = 0$$

where the modulus of force is denoted by $F$. Now, we define this time averaged force as the force applied between $2$ collisions. Thus,

$$ \langle F \rangle_t \approx \frac{F_0 \tau_C}{\tau_F} $$

where $\tau_F$ is the mean free time and $F_0$ is a consequence of mean-value theorem. I strongly suspect (but have no means of proving) that:

$$F_0 = PA$$

where $A$ is the area of the molecule. Can someone prove/disprove this?

  • I asked this before in a different light: https://physics.stackexchange.com/questions/749885/are-the-force-frequencies-the-same-in-the-discrete-and-continuous-case – More Anonymous Apr 18 '23 at 04:18

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