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What will happen if a photon rotating in LHC so fast it catches and bumps to itself?.

jmazaredo
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    What does "photon rotating in LHC" mean? Did you mean to ask about a proton revolving in the LHC? – PM 2Ring Dec 21 '23 at 16:43
  • BTW, they don't send single protons into the main ring of the LHC. A proton beam (initially) consists of 2808 bunches of protons, with ~120 billion protons per bunch. https://home.cern/resources/faqs/facts-and-figures-about-lhc – PM 2Ring Dec 21 '23 at 16:46

2 Answers2

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In QED there is no photon-photon vertex, meaning that two photons can only interact only via creation of electron-antielectron pairs (or other particle antiparticle "loops" ).

Mirella Luigia
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@Mirella Luigi Pozzi's answer address the theoretical concerns regarding:

$$ \gamma_1 + \gamma_2 \rightarrow \gamma_3 + \gamma_4 $$

though, you question seems to be about:

$$ \gamma_1 + \gamma_1 \rightarrow X $$

which doesn't makes sense in this context.

There are also experimental concerns:

  1. all photons with wavelengths $\lambda << R$, where $R$ is the radius of the beam-pipe travel at the speed of light, so the statement "goes so fast" doesn't really apply to light.

  2. A storage ring uses magnetic fields to confine charged particles in a (piece-wise) circular orbit. That works for protons and heavy nuclei, which the LHC stores.

Photons are neutral, and are not bent by the field, and cannot be stored in the LHC.

JEB
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