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Suppose, I somehow happen to dig a hole diametrically through the Earth (neglecting all constraints like molten core etc ) ... and I throw an object from one side of the hole, will it reach the other end?

Qmechanic
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user125892
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  • Yeah sure, if you ignore air friction and the rotation of the Earth and assume the Earth is a perfect sphere then you can drop it and it will fall all the way to the surface of the other side, and oscillate back and forth. – Brandon Enright Feb 03 '14 at 18:10
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    Possible duplicates: http://physics.stackexchange.com/q/7346/2451 and links therein. Related: http://physics.stackexchange.com/q/2481/2451 and links therein. – Qmechanic Feb 03 '14 at 18:11
  • Mass is responsible for gravity , why would it pass the centre if there is where the max mass exist ? – user125892 Feb 03 '14 at 18:24
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    No one says the mass *is* st the center; they say that *mathematically, you can treat the spherically distributed mass as if it were* at the center, and get the correct result... – DJohnM Feb 03 '14 at 20:23

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Drill through the spin axis, or the vacuum free fall trajectory scrapes the side from Coriolis force. Other than that,

http://hyperphysics.phy-astr.gsu.edu/hbase/mechanics/earthole.html

Uncle Al
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