How do I get the current Unix time in milliseconds (i.e number of milliseconds since Unix epoch January 1 1970)?
19 Answers
This:
date +%s
will return the number of seconds since the epoch.
This:
date +%s%N
returns the seconds and current nanoseconds.
So:
date +%s%N | cut -b1-13
will give you the number of milliseconds since the epoch - current seconds plus the left three of the nanoseconds.
and from MikeyB - echo $(($(date +%s%N)/1000000)) (dividing by 1000 only brings to microseconds)
You may simply use %3N to truncate the nanoseconds to the 3 most significant digits (which then are milliseconds):
$ date +%s%3N
1397392146866
This works e.g. on my Kubuntu 12.04 (Precise Pangolin).
But be aware that %N may not be implemented depending on your target system. E.g. tested on an embedded system (buildroot rootfs, compiled using a non-HF ARM cross toolchain) there was no %N:
$ date +%s%3N
1397392146%3N
(And also my (non rooted) Android tablet doesn't have %N.)
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1@warren: I saw that you edited and changed the
1397392146%3Nto1397392146%N, but the output of1397392146%3Nis that what I'd really seen on the busybox console of my android tablet. Could you explain your edit? – Joe Jun 25 '15 at 08:00 -
warren's comment from the history is "changed from 3 to 6, as 3 only takes you to microseconds". His edit seems entirely spurious; you should roll it back. – bukzor Dec 25 '15 at 00:27
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3This is a feature of GNU coreutils specifically. Ultimately, this is implemented in gnulib here: https://github.com/gagern/gnulib/blob/71090a2a314d9c378afd6f842abb49f60b42d4ef/lib/strftime.c#L1085. – telotortium Nov 06 '17 at 20:23
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1probably a dot in there makes sense.
date +%s.%3Nprints1510718281.134. – darksky Nov 15 '17 at 04:01 -
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@PeterMortensen Hard Float. ARM CPUs with hardware support for floating point numbers, as opposed to Soft Float where that has to be done slowly in software. – Different55 Jan 30 '20 at 17:28
date +%N doesn't work on OS X, but you could use one of
- Ruby:
ruby -e 'puts Time.now.to_f' - Python:
python -c 'import time; print(int(time.time() * 1000))' - Node.js:
node -e 'console.log(Date.now())' - PHP:
php -r 'echo microtime(TRUE);' - Elixir:
DateTime.utc_now() |> DateTime.to_unix(:millisecond) - The Internet:
wget -qO- http://www.timeapi.org/utc/now?\\s.\\N - or for milliseconds rounded to nearest second
date +%s000
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9Sure, you just have to wait for those interpreters to warm up. This works, too:
wget -qO- http://www.timeapi.org/utc/now?\\s.\\N– Camilo Martin Jun 23 '14 at 13:26 -
11Or, if you don't actually need the milliseconds but just the correct format:
date +%s000– Lenar Hoyt Apr 22 '15 at 16:15 -
@CamiloMartin: I love your (tongue-in-cheek?) wget exemple to get milliseconds precision out of a (remote) request to a website ^^. Locally, a few of the examples above are indeed probably closer to the tenth-of-a-second or maybe hundredth-of-a-second precision – Olivier Dulac Jan 22 '16 at 16:56
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@OlivierDulac yes, I wouldn't recommend that seriously! That said, it's far too common to see code that would break if someone, somewhere, decided to have some fun. Also, tenth-of-a-second?! In reality you can take the fractional part and redirect it to
/dev/randomto improve the system's entropy pool. – Camilo Martin Jan 22 '16 at 20:10 -
Perl:
echo "1487787384024" | perl -MTime::Piece -pe 's/(\d{13})/Time::Piece->localtime($1 \/1000)->strftime("%Y-%m-%d %a")/e'. The nice thing about this is that you can feed a whole line of text containing a 13-digit timestamp and it will perform a substitution and leave the rest of the text as-is – Sridhar Sarnobat Feb 28 '17 at 01:36 -
2https://apple.stackexchange.com/questions/135742/time-in-milliseconds-since-epoch-in-the-terminal has instructions for doing this in OSX via Brew's
coreutils– sameers Nov 17 '17 at 19:53 -
As @sameers pointed out: you can install
coreutilson macOS withbrew install coreutilsand thengdate +%Nwill work. – psmith May 18 '20 at 03:16 -
My solution is not the best, but it worked for me:
date +%s000
I just needed to convert a date like 2012-05-05 to milliseconds.
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Just throwing this out there, but I think the correct formula with the division would be:
echo $(($(date +%s%N)/1000000))
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For the people that suggest running external programs to get the milliseconds... at that rate, you might as well do this:
wget -qO- http://www.timeapi.org/utc/now?\\s.\\N
Point being: before picking any answer from here, please keep in mind that not all programs will run under one whole second. Measure!
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You're not asking the local system for the time. Which I guess is implied in the question. You also depend on a network connection. – orkoden Jan 29 '15 at 11:27
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2@orkoden The question explicitly asks for "number of milliseconds since Unix epoch January 1 1970". Also, I'm more of pointing out how you shouldn't ever fire up whole of Ruby or Python (or wget) just to get the time - either this is done through a fast channel or milliseconds don't matter. – Camilo Martin Jan 29 '15 at 11:57
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3Yes, I understood that you were giving a worse solution to highlight the bad solutions' flaws. I tried several solutions and measured the time. http://lpaste.net/119499 The results are kind of interesting. Even on a very fast i7 machine
datetakes 3 ms to run. – orkoden Jan 29 '15 at 12:38 -
@orkoden Nice testing! What OS? This might have to do with process spawning overhead. – Camilo Martin Jan 30 '15 at 13:18
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@orkoden Complementing that with a couple other platforms: http://pastebin.com/raw.php?i=q6Y6Beaj – Camilo Martin Jan 31 '15 at 08:19
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You're running
datetwice and then subtracting, while also usingawk. This seems to be inexact, becauseawkalso takes up some of that time. Why aren't you usingtime? – orkoden Jan 31 '15 at 11:08 -
@orkoden Both are run one next to the other in
bash's "command substitution" phase, and whenawksees them, they're just literal values. If you assume runningdatewill always take about the same time (which it seems to be), the difference between when one value was ready vs. when the next value was ready will give you the run time ofdateitself.timegives me way more fluctuation than doing this so I guesstimeis not very precise. – Camilo Martin Jan 31 '15 at 11:21 -
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2@Nakilon and this is why one shouldn't rely on curl-able conveniences like those for anything production. – Camilo Martin May 17 '17 at 22:24
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If you are looking for a way to display the length of time your script ran, the following will provide a (not completely accurate) result:
As near the beginning of your script as you can, enter the following
basetime=$(date +%s%N)
This'll give you a starting value of something like 1361802943996000000.
At the end of your script, use the following
echo "runtime: $(echo "scale=3;($(date +%s%N) - ${basetime})/(1*10^09)" | bc) seconds"
which will display something like
runtime: 12.383 seconds
Notes:
(1*10^09) can be replaced with 1000000000 if you wish
"scale=3" is a rather rare setting that coerces bc to do what you want. There are lots more!
I only tested this on Windows 7/MinGW... I don't have a proper *nix box at hand.
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Another solution for MacOS: GNU Coreutils
I have noticed that the MacOS' version of the date command is not interpreting the %N format sequence as nanoseconds but simply prints N to the output when I started using my .bashrc script from Linux, that's using it to measure how long executed commands run, on a MacOS machine.
After a little bit of research, I have learned that only the GNU date from the GNU Coreutils package does support milliseconds. Fortunately, it's pretty easy to install it on MacOS using Homebrew:
brew install coreutils
Since that package contains executables that are already present on MacOS, Coreutils' executables will be installed with a g prefix, so date will be available as gdate.
See for example this page for further details.
https://github.com/ysoftwareab/nanoseconds
I've just created this cross-platform project via golang to output nanoseconds since Unix epoch. As simple as that. Download your-platform-of-choice executable from a Github release.
Getting granular timestamps is important for benchmarks (e.g. OpenTelemetry). Depending on GNU/coreutils/insert-programming-language is in many cases a no go.
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Your answer could be improved with additional supporting information. Please [edit] to add further details, such as citations or documentation, so that others can confirm that your answer is correct. You can find more information on how to write good answers in the help center. – Community Jul 02 '22 at 17:19
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2This binary is ~3X faster than the python solution on my machine (10-12ms, vs 30ms with python). It runs with roughly the same speed as
date +%s%N. Nice! – Brandon Oct 15 '22 at 16:47
Additional solution since this question was originally asked in 2014. Bash 5.0 (released 2019) introduced two new built in variables
EPOCHREALTIME - The number of seconds since the Unix Epoch as a floating point value with micro-second granularity
EPOCHSECONDS - The number of seconds since the Unix Epoch
To obtain milliseconds since the Epoch, you can truncate the last three digits of microseconds to get milliseconds with ${EPOCHREALTIME::-3} and avoid the (expensive) call to date or other external programs.
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Here is how to get time in milliseconds without performing division. Maybe it's faster...
# test=`date +%s%N`
# testnum=${#test}
# echo ${test:0:$testnum-6}
1297327781715
Update: Another alternative in pure Bash that works only with Bash 4.2+ is the same as above, but use printf to get the date. It will definitely be faster, because no processes are forked off the main one.
printf -v test '%(%s%N)T' -1
testnum=${#test}
echo ${test:0:$testnum-6}
Another catch here though is that your strftime implementation should support %s and %N which is not the case on my test machine. See man strftime for supported options. Also see man bash to see printf syntax. -1 and -2 are special values for time.
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Seems like my
strftime(3)doesn't support%Nso no way forprintfto print nanoseconds. I am using Ubuntu 14.04. – haridsv Mar 21 '17 at 07:35 -
@haridsv, yeah, it's not in glibc.
dateseems like the more reliable option. – akostadinov Mar 22 '17 at 10:26
(repeat from previous answers) date +%N doesn't work on OS X, but you could also use:
Perl (requires Time::Format module). Perhaps it is not the best CPAN module to use, but it gets the job done. Time::Format is generally made available with distributions.
perl -w -e'use Time::Format; printf STDOUT ("%s.%s\n", time, $time{"mmm"})'
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The OP specifically asked for ways to do it using bash. How is this bash, save as a method to launch something else? – MadHatter Mar 15 '16 at 10:48
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1I use this in my bash shell scripts ... under OSX. So,
datecan't be used and there is no bash-only commands that answer the need. – TVNshack Mar 15 '16 at 13:37 -
Fair enough. If you were to clarify why OSX's
datecan't be used as part of your answer, I'd remove my downvote. – MadHatter Mar 15 '16 at 13:43 -
This was explained a few answers above. I couldn't add as comment that command which was missing with the proposed list. So I've added it here. – TVNshack Mar 15 '16 at 14:56
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Fair enough, I accept this is a useful addition to the canon. +1 from me! – MadHatter Mar 15 '16 at 15:32
The most accurate timestamp we can get for Mac OS X is probably this:
python3 -c 'import datetime; print(datetime.datetime.now().strftime("%s.%f"))'
1490665305.021699
But we need to keep in mind that it takes around 30 milliseconds to run. We can cut it to the scale of 2 digits fraction, and at the very beginning compute the average overhead of reading the time, and then remove it off the measurement. Here is an example:
function getTimestamp {
echo `python -c 'import datetime; print datetime.datetime.now().strftime("%s.%f")' | cut -b1-13`
}
function getDiff {
echo "$2-$1-$MeasuringCost" | bc
}
prev_a=`getTimestamp`
acc=0
ITERATIONS=30
for i in `seq 1 $ITERATIONS`;do
#echo -n $i
a=`getTimestamp`
#echo -n " $a"
b=`echo "$a-$prev_a" | bc`
prev_a=$a
#echo " diff=$b"
acc=`echo "$acc+$b" | bc`
done
MeasuringCost=`echo "scale=2; $acc/$ITERATIONS" | bc`
echo "average: $MeasuringCost sec"
t1=`getTimestamp`
sleep 2
t2=`getTimestamp`
echo "measured seconds: `getDiff $t1 $t2`"
You can uncomment the echo commands to see better how it works.
The results for this script are usually one of these 3 results:
measured seconds: 1.99
measured seconds: 2.00
measured seconds: 2.01
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For Alpine Linux (many Docker images) and possibly other minimal Linux environments, you can abuse adjtimex:
adjtimex | awk '/(time.tv_usec):/ { printf("%06d\n", $2) }' | head -c3
adjtimex is used to read (and set) kernel time variables. With awk you can get the microseconds, and with head you can use the first 3 digits only.
I have no idea how reliable this command is.
Note: Shamelessly stolen from this answer
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adjtimexreturnsadjtimex: Function not implementedunder Alpine for me. – sakra Sep 08 '21 at 18:02
Perl solution
perl -mTime::HiRes -e 'printf "%.0f\n", (Time::HiRes::time() * 1000 )'
Time::HiRes::time() returns a float of the form unixtimeinsec.microseconds
Multiply by 1000 to shift left 3 digits, and output with no decimal digits.
Why not just convert to integer with %d?
Because it'll overflow a signed (or unsigned) integer on a 32 bit OS, such
as our ancient AIX servers.
As others have pointed out, it's a question of portability. The accepted answer works on linux or anything that can run gnu date, but not on several other UNIX flavors. Personally I find our older systems are much more likely to have perl than python, Node.js, Ruby or PHP.
Yes, date +%s%3N (if available) is about 5x faster than perl).
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Using date and expr can get you there i.e.
X=$(expr \`date +%H\` \\* 3600 + \`date +%M\` \\* 60 + \`date +%S\`)
echo $X
Just expand on it to do whatever you want
I realise this does not give milliseconds since epoch, but it might still be useful as an answer for some of the cases, it all depends on what you need it for really, multiply by 1000 if you need a millisecond number :D
Simplest way would be to make a small executable (from C f.ex.) and make it available to the script.
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There's a potential problem running
datemultiple times. In some cases, the date or time may change between runs as your command is written. It's better to rundateonce and parse the parts out and do your calculation. One of several ways to do that would bet=$(date +%H%M%S); (( x = ${t:0:2} * 3600 + ${t:2:2} * 60 + ${t:4:2} )); echo "$x". This uses Bash syntax since the question is tagged [tag:bash]. As you allude, your answer (and my variation) only gives seconds for the current day so far and not since the Epoch and not in millis. – Dennis Williamson Nov 04 '15 at 00:17
Putting the previous responses all together, when in OS X,
ProductName: Mac OS X
ProductVersion: 10.11.6
BuildVersion: 15G31+
you can do like
microtime() {
python -c 'import time; print time.time()'
}
compute() {
local START="$(microtime)"
#$1 is command $2 are args
local END="$(microtime)"
DIFF="$(bc <<< "$END - $START")"
echo "$1\t$2\t$DIFF"
}
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Not adding anything revolutionary here over the accepted answer, but just to make it reusable easily for those of you whom are newer to Bash. Note that this example works in OS X and on older Bash which was a requirement for me personally.
nowInMs() {
echo "$(($(date +'%s * 1000 + %-N / 1000000')))"
}
Now you can run
TIMESTAMP="$(nowInMs)";
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Are you sure you don't have
$(brew --prefix)/opt/coreutils/libexec/gnubinin your$PATH?On my macOS 12.7:
/bin/date +'%s * 1000 + %-N / 1000000'gives1710943086 * 1000 + N / 1000000Only the gnu version interprets
– DouglasDD Mar 20 '24 at 14:02%N:$(brew --prefix)/opt/coreutils/libexec/gnubin/date +'%s * 1000 + %-N / 1000000'to give1710943233 * 1000 + 044024 / 1000000
If you want a simple shell elapsed computation, this is easy and portable, using Frank Thonig's answer:
now() {
python -c 'import datetime; print datetime.datetime.now().strftime("%s.%f")'
}
seismo:~$ x=`now`
seismo:~$ y=`now`
seismo:~$ bc <<< "$y - $x"
5.212514
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echo $(($(date +%s%N)/1000))– MikeyB Jun 14 '10 at 16:38%Ndoes not work on OSX Yosemite – Matt Clark Jun 03 '15 at 20:32datecommand for nanoseconds – warren Jun 03 '15 at 20:56gdate +%s%N– rymo Sep 05 '15 at 15:09cut -b1-13, one could use the bash substring:dt=$(date +%s%N); ${dt:1:13}. – haridsv Mar 21 '17 at 08:46date +%s%Nactually be this, to insert the decimal between the seconds and nanoseconds?:date +%s.%N– Gabriel Staples Dec 27 '20 at 22:37