In order to get a diagonal line in a cell, I picked up a piece of code from Diagonal lines in table cell
The code adapted to my situation works fine until I decide to use multirow.
Here is the MWE.
\documentclass{article}
\usepackage{multirow}
\usepackage{tikz}
\newcommand\diag[4]{%
\multicolumn{1}{p{#2}|}{\hskip-\tabcolsep
$\vcenter{\begin{tikzpicture}[baseline=0,anchor=south west,inner sep=#1]
\path[use as bounding box] (0,0) rectangle (#2+2\tabcolsep,\baselineskip);
\node[minimum width={#2+2\tabcolsep},minimum height=\baselineskip+\extrarowheight] (box) {};
\draw (box.north west) -- (box.south east);
\node[anchor=south west] at (box.south west) {#3};
\node[anchor=north east] at (box.north east) {#4};
\end{tikzpicture}}$\hskip-\tabcolsep}}
\begin{document}
\begin{tabular}[t]{|c|c|c|}
\hline
\multirow{2}{*}{\diag{.1em}{.5cm}{$a$}{$i$}}&\multicolumn{2}{c|}{A}\\\cline{2-2}
&1\\
\end{tabular}
\end{document}
This produces an error message,
! Misplaced \omit. \multispan ->\omit
\@multispan l.20 ...ultirow{2}{*}{\diag{.1em}{.5cm}{$a$}{$i$}}
&\multicolumn{2}{c|}{A}\\\...
If I omit the \multirow part this works fine.
