The answer of egreg has the tiny drawback, that the values for \tleq has to be found manually. This answer fills the gap.
Package amsmath processes its equations twice. In the first run, the widths are measured.
The switch \ifmeasure@ is true during this measuring phase.
In the second run the equations are actually typeset. Depending on the measured widths of the first run amsmath is now able to move the equation number if necessary, for example.
Also environment alignat* stores the widths of the cells and calculates the maximal widths of the columns.
After the measuring phase the widths of the columns are available in macro \maxcolumn@width. The values are prefixed with \or for easy use with \ifcase, e.g.:
\or 23.1945pt \or 25.221pt \or 10.00002pt \or 12.77773pt \or 54.77959pt \or 62.81717pt \or 74.90263pt \or 0.0pt \or 0.0pt
Count register \column@ holds the current column number.
The following example defines the macro \tline that uses these data to draw a line with the width of the current column. In right aligned columns it is placed after the cell contents, in left aligned columns \tline should start the cell.
\documentclass{article}
\usepackage{amsmath}
\makeatletter
\newcommand*{\tline}{%
\ifmeasuring@
% first measuring run
\else
% second run
% \typeout{\meaning\maxcolumn@widths}% debug info
\ifodd\column@
\expandafter\rlap
\else
\expandafter\llap
\fi
{%
\vrule height-1ex depth \dimexpr1ex+.4pt\relax width
\ifcase\numexpr\column@+1\expandafter\relax
\maxcolumn@widths
\fi
}%
\fi
}
\makeatother
\begin{document}
\begin{alignat*}{4}
a^1 x^\star &\leq b_1 &\quad& \Rightarrow & \delta_1 a^1 x^\star &\leq
\delta_1 b_1 \\
a^2 x^\star &\leq b_2 && \Rightarrow & \delta_2 a^2 x^\star &\leq
\delta_2 b_2 \\[-4.5pt]
&\;\;\vdots && \;\;\vdots & &\;\;\vdots \\
a^m x^\star &\leq b_m && \Rightarrow & \delta_m a^m x^\star
\tline&\tline \leq\delta_m b_m \quad (+) \\
&&&& \sum_{1 \leq i \leq m} \delta_i a^i x^\star &\leq \delta_i b_i &
\quad\Rightarrow \delta^t A x^\star \leq \delta^t b
\end{alignat*}
\end{document}

Remark:
- The space above
\vdots is a little large for my taste, macro \vdots already adds 6pt at the top of the dots. Therefore I have reduced it a bit.
\cline in alignat* and better vertical centered dots
An easier solution is \cline, it also works in environment alignat*, only the space before needs some adjusting.
\rvdots of egreg's answer (see Qrrbrbirlbel's comment) cheats a little, it reduces the height by 1pt. The example below defines \mvdots that uses \vcenter instead of \vbox that reduces the asymmetry by participating the descender.
Example file:
\documentclass{article}
\usepackage{amsmath}
\makeatletter
\DeclareRobustCommand{\mvdots}{%
\vcenter{%
\baselineskip4\p@\lineskiplimit\z@
\hbox{.}\hbox{.}\hbox{.}%
}%
}
\makeatother
\begin{document}
\begin{alignat*}{4}
a^1 x^\star &\leq b_1 &\quad& \Rightarrow & \delta_1 a^1 x^\star &\leq
\delta_1 b_1 \\
a^2 x^\star &\leq b_2 && \Rightarrow & \delta_2 a^2 x^\star &\leq
\delta_2 b_2 \\
&\;\;\mvdots && \;\;\mvdots & &\;\;\mvdots \\
a^m x^\star &\leq b_m && \Rightarrow & \delta_m a^m x^\star
& \leq\delta_m b_m \quad (+) \\[-2ex]
\cline{5-6}
&&&&\sum_{1 \leq i \leq m} \delta_i a^i x^\star &\leq \delta_i b_i &
\quad\Rightarrow \delta^t A x^\star \leq \delta^t b
\end{alignat*}
\end{document}

\rvdotsmight be useful here too: How to vertically center the \vdots in this node? – Qrrbrbirlbel Jun 21 '13 at 01:17\tlinecommands in the wrong line of my code and, when I compiled it, I realized that if the line should go above the summation, its index would be crossed by the added line... (try putting them in the line of the summation) For the purposes of this question, your answer is great! But what if I needed it in this other scenario? Do you have any ideas on how to fix this? – Arthur Araruna Jun 21 '13 at 01:39