2

The mathtools package has a centered colon, \vcentcolon, which is used to display the definition symbol := correctly.

However when using the fourier package, I get the following output

enter image description here

from

$:\vcentcolon=$

where I have added a normal colon as comparison.

The second colon is slightly adjusted, but not entirely centered upon the =. How do I get \vcentcolon: right?

Deniz
  • 664
  • 1
    You might want to take a look at this answer. – A.Ellett Jul 22 '13 at 14:58
  • 1
    It's the first : that doesn't look right to me. Why not write \vcentcolon\vcentcolon=? – A.Ellett Jul 22 '13 at 15:00
  • The first colon is just for illustration here. I would like $\vcentcolon=$ to be adjusted correctly. – Deniz Jul 22 '13 at 15:13
  • @A.Ellett The solutions in the link do the work because they do not use the colon symbol but construct their own dots instead. Thanks for that. I wonder if there is a solution that uses the actual colon... – Deniz Jul 22 '13 at 15:26

1 Answers1

2

Here are two homegrown possibilities (converted from comments into an answer) in which the colon dots match the height of the equals bars:

\documentclass{article}
\usepackage{fourier}
\usepackage{stackengine}
% THE FOLLOWING WORKS WHEN fourier PACKAGE IS NOT USED
\newcommand\newvcentcolon{\abovebaseline[.07ex]{\stackanchor[.18ex]{.}{.}}}
%\newcommand\newvcentcolon{\abovebaseline[.02ex]{\stackanchor[.19ex]{.}{.}}}
\newcommand\colonequalA{\mathrel{\newvcentcolon{=}}}

\usepackage{scalerel}
% THE FOLLOWING WORKS WHEN fourier PACKAGE IS NOT USED
%\newcommand\colonequalB{\mathrel{\hstretch{.085}{=}\hspace{.2ex}{=}}}
\newcommand\colonequalB{\mathrel{\hstretch{.13}{=}\hspace{.2ex}{=}}}

\begin{document}

\(x\colonequalA x+1\)

\(x \colonequalB x+1 \)

\end{document}

enter image description here

Steven B. Segletes
  • 237,551