\Theta with square

Question

I'm using \Theta for some concept in my work, then I need a variation of such concept. I was thinking to use \Theta symbol with a square instead of a circle.

How can I obtain such symbol?

Thanks

Would \boxminus be ok? You need to load amssymb to use it. — Philipp, Oct 02 '13 at 05:30
I don't think those symbols would be that distinguishable. Why not use an alternative symbol? Or perhaps \Theta'? — Werner, Oct 02 '13 at 05:49
Check out:
http://tex.stackexchange.com/questions/13594/how-to-add-a-custom-symbol-to-latex

http://stackoverflow.com/questions/3257923/how-to-make-your-own-latex-math-symbol — Louis, Oct 02 '13 at 06:21
You can try to use a reverse search like detexify. No much luck there, the best was \boxminus from amssymb package. You can also try to include a previously made image, but it can be a pain to use. — masu, Oct 02 '13 at 06:13
The “circle” in \Theta is not geometric, while a square is; I don't think a visual connection would be obvious. — egreg, Oct 02 '13 at 13:38
Sorry, but introducing a new own letter, that doesn't have a name, doesn't sound like a good idea. Certainly if I were reviewing your paper, I would not allow this through. Both @Werner 's suggestions sound great: \Theta', \Xi, \Theta_1, \tilde\Theta, ... do you really need a new symbol? — yo', Oct 29 '13 at 22:33

score 10 · Accepted Answer · answered Oct 29 '13 at 22:27

A solution with TikZ:

\documentclass{article}

\usepackage{tikz}
\usetikzlibrary{calc}

\newlength\thetawidth
\newlength\thetaheight

\newcommand*{\SquareTheta}{%
  \begingroup
    \setlength{\mathsurround}{0pt}%
    \settowidth{\thetawidth}{$\Theta$}%
    \settoheight{\thetaheight}{$\Theta$}%
    \begin{tikzpicture}[
      x=\thetawidth,
      y=\thetaheight,
    ]
    \draw[line width=.1\thetawidth, line cap=round]
      (0.125,.05\thetawidth) -- +($(0,1)-(0,.1\thetawidth)$)
      (0.875,.05\thetawidth) -- +($(0,1)-(0,.1\thetawidth)$);
    \draw[line width=.05\thetaheight, line cap=butt]
      (0.125,.025\thetaheight) -- +(0.75,0)
      ($(0.125,1)-(0,.025\thetaheight)$) -- +(0.75,0);
    \draw[line width=.1\thetawidth, line cap=butt]
      (0.275,0.5) -- (0.725,0.5);
    \draw[line width=.0375\thetaheight, line cap=butt]
      ($(0.275,0.5)-(0,.1\thetawidth)$) -- +(0,.2\thetawidth)
      ($(0.725,0.5)-(0,.1\thetawidth)$) -- +(0,.2\thetawidth);
    \end{tikzpicture}%
  \endgroup
}

\begin{document}
\renewcommand*{\arraystretch}{0}
\begin{tabular}{c}
  $\Theta$ \\[1pt]
  $\SquareTheta$ \\[1pt]
  $\Theta\SquareTheta$
\end{tabular}
\end{document}

\Theta with square

1 Answers1