Positioning a tikz scope relative to another tikz scope

Question

In the manual of PGFplots on page 333 the author describes how to position an axis environment relative to another axis environment:

\begin{tikzpicture}
    \begin{axis}[name=plot1,height=3cm,width=3cm]
        \addplot coordinates {(0,0) (1,1) (2,2)};
    \end{axis}
    \begin{axis}[name=plot2,at={($(plot1.east)+(1cm,0)$)},anchor=west,height=3cm,width=3cm]
         \addplot coordinates {(0,2) (1,1) (2,0)};
    \end{axis}
\end{tikzpicture}

Unfortunately, the same for scopes,

\begin{tikzpicture}
    \begin{scope}[name=scope1]
         \draw (1,2) rectangle (3,4);
    \end{scope}
    \begin{scope}[at={($(scope1.east)+(1cm,0)$)},anchor=west]
         \draw (5,6) rectangle (7,8);
    \end{scope}
\end{tikzpicture}

, does not work. How can I get it to work? I am not interested in absolute positioning, but merely in relative positioning.

@Adriaan -- wrap the the second case -- scope environment -- by axis environment and apply the same skill of the first case for the newly-wrapped axis environment. — Jesse, Nov 11 '13 at 15:29

score 46 · Accepted Answer · answered Nov 11 '13 at 17:55

46

Here is a solution using local bounding box to get the bounding box of the first scope and using shift to define the origin of the second scope:

\documentclass[tikz]{standalone}
\usetikzlibrary{calc}
\begin{document}
\begin{tikzpicture}
  \begin{scope}[local bounding box=scope1]
    \draw (2,2) rectangle (3,4);
  \end{scope}
  \begin{scope}[shift={($(scope1.east)+(1cm,0)$)}]
    \draw (0,0) rectangle (2,1);
  \end{scope}
\end{tikzpicture}
\end{document}

enter image description here

answered Nov 11 '13 at 17:55

Paul Gaborit

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This works well, if the second scope only uses positive x coordinates. If the scope also "grows to the left", this is not taken into account? Any idea how to do that? If possible without nested tikzpictures... – ingomueller.net Apr 27 '15 at 13:44
@ingomueller.net This method allows to determine the origin of the second scope. The contents of the second scope is not taken into account... – Paul Gaborit Apr 27 '15 at 16:49
Thanks for the reply! I guess I'll have to use the solution with nested tikzpictures then. – ingomueller.net Apr 28 '15 at 16:57
What if I am not interested to position but not interested to draw the local bounding box? You could add a mention of draw=none. – Viesturs May 06 '21 at 10:15
@Viesturs Here, the local bounding box is not drawn... – Paul Gaborit May 06 '21 at 12:50
1

@Viesturs You can use draw=none or replace \draw by \path. – Paul Gaborit May 06 '21 at 12:52

Bordaigorl · Answer 2 · 2018-08-15T08:45:33.747

Edit: the answer below is here for reference but note that nesting tikzpictures is discouraged due to some subtle side-effects that this may cause. In most cases, to build a "modular" picture you can use the pic action documented in Chapter 18 of the documentation. In simpler cases like the one in the question, a combination of shift and fit usually suffices.

If you need to keep the two scopes separated and wish to use them as "modules" I would suggest you use two nodes with nested tikzpictures as in

\begin{tikzpicture}
    \node(scope1){
        \begin{tikzpicture}
           \draw (1,2) rectangle (3,4);
        \end{tikzpicture}
    };
    \node[at={($(scope1.east)+(1cm,0)$)},anchor=west] (scope2){
        \begin{tikzpicture}
             \draw (5,6) rectangle (7,8);
        \end{tikzpicture}
    };
\end{tikzpicture}

I would actually not propose to nest tikzpictures as this may bring some complications. — , Aug 13 '18 at 19:39

Positioning a tikz scope relative to another tikz scope

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