I am trying to draw a two curved lines that form a chiasmata. I am imagining it would look like an 'X' that is composed of two CURVED lines such that it is wider than it is tall.
I also want to place four words, one at the end of each line. I want it to look something like this:
With tikz:
\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{positioning}
\begin{document}
\begin{tikzpicture}
\node[align=right,anchor=east] at(0,0) (a) {Tragedy};
\node[below=1cm of a.east,anchor=east] (b) {Appearence};
\node[right=2cm of a,anchor=west] (c) {Comedy};
\node[below=1cm of c.west,anchor=west] (d) {Reality};
\draw (a) edge[out=0, in=180] (d);
\draw (b) edge[out=0, in=180] (c);
\end{tikzpicture}
\end{document}
With bazier curves:
\documentclass[tikz,border=10pt]{standalone}
\usepackage{tikz}
\usetikzlibrary{positioning}
\begin{document}
\begin{tikzpicture}[font=\sffamily]
\node[align=right,anchor=east] at(0,0) (a) {Tragedy};
\node[below=1cm of a.east,anchor=east] (b) {Appearence};
\node[right=2cm of a,anchor=west] (c) {Comedy};
\node[below=1cm of c.west,anchor=west] (d) {Reality};
\draw (a.east) .. controls (2,-0.35) and (0,-0.65).. (d.west);
\draw (b.east) .. controls (2,-0.65) and (0,-0.35).. (c.west);
\end{tikzpicture}
\end{document}
And little cheating ;)
\documentclass[tikz,border=10pt]{standalone}
\usepackage{tikz}
\usetikzlibrary{positioning}
\begin{document}
\begin{tikzpicture}[font=\sffamily]
\node[align=right,anchor=east] at(0,0) (a) {Tragedy};
\node[below=1cm of a.east,anchor=east] (b) {Appearence};
\node[right=2cm of a,anchor=west] (c) {Comedy};
\node[below=1cm of c.west,anchor=west] (d) {Reality};
\draw[olive,thick] (a) edge[out=0,in=0,distance=1.335cm] (b);
\draw[olive,thick] (c) edge[out=180,in=180,distance=1.335cm] (d);
\end{tikzpicture}
\end{document}
And the last change. If you are finding it difficult to handle bazier curve controls, this is just another short cut:
\documentclass[tikz,border=10pt]{standalone}
\usepackage{tikz}
\usetikzlibrary{positioning}
\begin{document}
\begin{tikzpicture}[font=\sffamily]
\node[align=right,anchor=east] at(0,0) (a) {Tragedy};
\node[below=1cm of a.east,anchor=east] (b) {Appearence};
\node[right=2cm of a,anchor=west] (c) {Comedy};
\node[below=1cm of c.west,anchor=west] (d) {Reality};
\path[draw=none] (a) -- (d) coordinate[midway] (m);
\draw (a) edge[out=0,in=90] (m)
(m) edge[out=270,in=180] (d);
\draw (b) edge[out=0,in=270] (m)
(m) edge[out=90,in=180] (c);
\end{tikzpicture}
\end{document}
tragedy: you missed the reality of appearance, hence it's comedy guess where ? :)
– texenthusiast
Feb 26 '14 at 23:21
\path[draw=none] (a) -- (d) node[midway,inner sep=0.5pt] (m){}; \draw (a) edge[out=0,in=110] (m.110) (m.290) edge[out=290,in=180] (d); \draw (b) edge[out=0,in=250] (m.center) (m.center) edge[out=70,in=180] (c);
–
Feb 26 '14 at 23:59
Since the curve has all the appearance of the kappa curve, we can plot the kappa curve with pst-plot, given its polar equation (ρ = a/ tan θ):
\documentclass[11pt, a4paper]{article}
\usepackage[utf8]{inputenc}
\usepackage[T1]{fontenc}
\usepackage{lmodern}
\usepackage[svgnames,pdf]{pstricks}
\usepackage{pst-plot}
\begin{document}
\psset{unit=0.8cm}
\begin{pspicture}(-4,-4)(4,4)
\sffamily
\psset{linewidth = 1pt, linecolor = IndianRed, plotpoints=200, plotstyle=curve, polarplot, algebraic, labelsep = 0.5em}
\psclip{\pscircle[linestyle=none]{2.5}}%
\psplot{0.5}{3}{1.5*cos(x)/sin(x)}
\psplot{-0.5}{-3}{1.5*cos(x)/sin(x)}
\endpsclip
\uput[r](2.5; 32){Comedy} \uput[r](2.5; -32){Reality}
\uput[l](-2.5; 32){Tragedy} \uput[l](-2.5; -32){Appearance}
\end{pspicture}
\end{document}
This gives:
With Metapost:
prologues := 3;
outputtemplate := "%j%c.eps";
beginfig(1);
z0 = right scaled 60;
z1 = -z3 = z0 rotated 30;
z4 = -z2 = z0 rotated -30;
path p[];
p1 = z2 {right} .. {right} z4;
p2 = z3 {right} .. {right} z1;
draw p2; undraw p1 withpen pencircle scaled 4; draw p1;
defaultfont := "phvr8r";
label.lft("Tragedy",z2);
label.lft("Appearance",z3);
label.rt("Comedy",z1);
label.rt("Reality",z4);
endfig;
end.
which tries to place an emphasis on the crossing by making one line fly over the other.
If you would rather keep some ambiguity and make the shape a little less chi-like, you could try bending the paths to the vertical where they cross and perhaps getting rid of the undraw, like this:
p1 = z2 {right} .. {down} origin .. {right} z4;
p2 = z3 {right} .. {up} origin .. {right} z1;
draw p1; draw p2;
which changes the above picture to produce something more like the OP diagram
Done by stacking and rotating text symbols.
\documentclass{article}
\usepackage{graphicx}
\usepackage{stackengine}
\begin{document}
\def\stackalignment{r}\stackanchor[10pt]{Tragedy}{Appearance}
\abovebaseline[-10pt]{\scalebox{3}{\rotatebox{90}{$\bigcup$}\kern-.8pt\rotatebox{90}{$\bigcap$}}}
\def\stackalignment{l}\stackanchor[10pt]{Comedy}{Reality}
\end{document}
run with xelatex
\documentclass{article}
\usepackage{pst-node}
\begin{document}
\noindent
\makebox[3cm][r]{\rnode{ul}{Tragedy}}\hspace{3cm}\rnode{ur}{Comedy}\\[1.25cm]
\makebox[3cm][r]{\rnode{ll}{Appearence}}\hspace{3cm}\rnode{lr}{Reality}
\nccurve[nodesep=5pt,angleB=180]{ul}{lr}
\nccurve[nodesep=5pt,angleB=180,border=2pt]{ll}{ur}
\end{document}
Warming up with PSTricks.
\documentclass[preview,border=12pt]{standalone}
\usepackage{pst-node}
\begin{document}
\begin{psmatrix}[colsep=3cm,nodesep=2mm,arm=1.3,linearc=1]
[mcol=r]Tragedy & [mcol=l]Comedy\\
[mcol=r]Appearence & [mcol=l]Appearence
\ncdiag{1,1}{2,1}
\ncdiag[angle=180]{1,2}{2,2}
\end{psmatrix}
\end{document}
\documentclass[preview,border=12pt]{standalone}
\usepackage{pst-node}
\begin{document}
\begin{psmatrix}[colsep=3cm,nodesep=5pt,angleB=180]
[mcol=r]Tragedy & [mcol=l]Comedy\\
[mcol=r]Appearence & [mcol=l]Appearence
\nccurve{1,1}{2,2}
\nccurve[border=2pt]{2,1}{1,2}
\end{psmatrix}
\end{document}
\documentclass[preview,border=12pt]{standalone}
\usepackage{pst-node}
\begin{document}
\begin{psmatrix}[colsep=3cm,nodesep=5pt,angleB=180]
[mcol=r]Tragedy & [mcol=l]Comedy\\
[mcol=r]Appearence & [mcol=l]Appearence
\ncdiag{1,1}{2,2}
\ncdiag[border=2pt]{2,1}{1,2}
\end{psmatrix}
\end{document}
tragedy: you missed the reality of appearance, hence it's comedy guess where ? :)
– texenthusiast
Feb 26 '14 at 23:22
appearance was twice and missed the reality http://tex.stackexchange.com/questions/162475/can-anyone-draw-a-chiasma-in-latex/162560?noredirect=1#comment372628_162490
– texenthusiast
Feb 27 '14 at 03:43
You can do it with xypic:
\documentclass{article}
\usepackage[all]{xypic}
\usepackage{amsmath}
\begin{document}
\begin{equation*}\xymatrix@R=5mm@C=2cm{
\txt{Tragedy} \ar@{- }@(r,l)[dr] & \txt{Comedy}\\
\txt{Appearance} \ar@{- }@(r,l)[ur] & \txt{Reality}
}\end{equation*}
\end{document}
@R=5mm and @C=2cm set the column and row sizes. @{- } removes arrow heads and @(r,l) gives the lines their curvature. You can do a lot more with xypic.
