I would like to intersect arc and sloped line as it's discribed in the code after having rotated the sloped line. Why doesn't the red point belong to sloped line? I hope my question is quite clear for uptake.
\documentclass[12pt,a4paper]{article}
\usepackage{russ}
\usepackage[left=1cm,right=1cm,top=2cm,bottom=2cm]{geometry}
\usepackage{tikz} % Для рисования мега-картинок прямо здесь
\usepackage{rotating}
\usetikzlibrary{calc,intersections} % Читайте мануал в Bonus/Books on TeX/Pictures for TeX/PGF, а также http://www.texample.net/tikz/examples/all/
\colorlet{examplefill}{yellow!80!black}
\begin{document}
\begin{figure}
\begin{tikzpicture}[scale=3]
/cs/horizontal line through={(1,1)}
\path [name path=arc] (0.5cm,0) arc (0:90:0.5cm);
\draw (0,0) ellipse (0.7cm and 2.2cm);
\draw[name path=simple line] (-1,0) -- (1,0) coordinate (x axis);
\draw (0,-2.5) -- (0,2.5) coordinate (y axis);
\begin{turn}{50}
\draw[name path=sloped line] (-2.5,0) -- (2.5,0) coordinate (x axis);
\draw (0,-1.5) -- (0,1.5) coordinate (y axis);
\draw (0,0) ellipse (2cm and 1cm);
\end{turn}
\fill[red,name intersections={of=sloped line and arc, by=s}]
(s) circle (2pt) node[above=3] {a};
\end{tikzpicture}
\centering
\label{elliptic polarization}
\end{figure}
\end{document}
And how to output coordinates of the intersection point instead of a?!

