8

I want to use a slanted \sum symbol denoting a different meaning from summation. How do I get a slanted \sum symbol?

enter image description here

Werner
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ccdfafd
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    What is the intended meaning? Please reconsider this as the use of 2 very similar symbols, only distinguished by the fact that one is slanted, will be extremely confusing, as well as typographically bad. In mathematical typesetting, things of the same kind get typeset in similar ways e.g. all functions, all operators, all variables... in upright, in italic, in ... – cfr Jan 03 '15 at 02:45
  • Can you draw what you're looking for? If it's a simple rotation, then the linked answers your question. If it's truly 'oblique', then perhaps not. – Sean Allred Jan 03 '15 at 04:27
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    @cfr This is not duplicate, because rotating isn't slanting. – wipet Jan 03 '15 at 07:54

4 Answers4

8

If you are using pdfTeX then you can try this code:

\def\itsum{\mathop{\mathpalette\itsumA{}\phantom\sum}}
\def\itsumA#1#2{\pdfsave\pdfliteral{1 0 .2 1 0 0 cm}\rlap{$#1\sum$}\pdfrestore}

$\sum_i^5 \itsum_j^{\,7} a_{ij}$

sumy

wipet
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    Also works with LuaTeX 'out of the box' (those primitives are carried forward as-is) – Joseph Wright Jan 03 '15 at 14:23
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    @JosephWright Of course. I "assume" :-) that LuaTeX users know that pdfTeX is included here. – wipet Jan 03 '15 at 14:26
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    Actually you can generalize it with something like {if pdf}{<\pdfliteral code>}{<\special code>} – percusse Jan 04 '15 at 03:37
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    @percusse I do something similar in my macros. If \pdfliteral isn't accessible then I define it as \def\pdfliteral#1{\special{pdf:literal #1}}. This allows me to keep the \pdfliteral-dependent macros unchanged. – wipet Jan 04 '15 at 06:58
6

One way to do it is to use a slanted capital sigma. By using the scalerel package, one can make that symbol (approximately) the same size as the original \sum operator:

\documentclass{article}
\usepackage{amsmath}
\usepackage{scalerel}
\DeclareMathOperator*{\itsum}{\scalerel*{\mathit{\Sigma}}{\sum}}
\begin{document}
\[
\sum_i x_i\quad\itsum_i x_i
\]
\end{document}

enter image description here

summer
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    Why did you make the slanted version larger? – cfr Jan 03 '15 at 03:25
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    @cfr The reason the slanted one is larger can be determined by executing \fboxsep=0pt\fbox{$\mathit{\Sigma}$}\fbox{$\displaystyle\sum$} (with the scalerel package loaded). The \sum has a built in padding above and below the glyph, which is absent in the \Sigma (\mathit or otherwise). Thus, the \scalreled \Sigma is grown to the size of the padded \sum, which is slightly larger than the actual glyph. – Steven B. Segletes Jan 03 '15 at 04:20
4

You can simply use \varSigma as $\varSigma$

enter image description here

CompetitiveLin
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3

With l3draw (and the standard \mathpalette)

\documentclass{article}
\usepackage{amsmath}
\usepackage{l3draw}

\makeatletter
\NewDocumentCommand{\slsum}{}{%
  \DOTSB
  \mathop{\vphantom{\sum}\mathpalette\slsum@\relax}
  \slimits@
}
\NewDocumentCommand{\slsum@}{mm}{%
  \vcenter{\hbox{%
    \xslantobject{$\m@th#1\sum$}{0.4}%
  }}%
}
\makeatother


\ExplSyntaxOn


\NewDocumentCommand{\xslantobject}{mm}
 {
  \draw_begin:
  \draw_transform_xslant:n { #2 }
  \hbox_set:Nn \l_tmpa_box { #1 }
  \draw_box_use:N \l_tmpa_box
  \draw_end:
 }


\ExplSyntaxOff


\begin{document}


[
\sum_{i\ge0}\slsum_{i\ge0}
]
\begin{center}
$\sum\slsum$
\end{center}


\end{document}

enter image description here

egreg
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