I'm new to both GeoGebra and TikZ so my question might be silly.
I used GeoGebra to draw the distribution function of a Cauchy distribution, which is
F(x) = 1/\pi \arctan(10(x-0.5))+0.5.
Here is the plot I did in GeoGebra

and this is the TikZ code generated by the GeoGebra

or
\documentclass[10pt]{article}
\usepackage{pgf,tikz}
\usetikzlibrary{arrows}
\pagestyle{empty}
\begin{document}
\begin{tikzpicture}[line cap=round,line join=round,>=triangle 45,x=1.0cm,y=1.0cm]
\draw[->,color=black] (-0.6,0.) -- (1.6,0.);
\foreach \x in {-0.4,-0.2,0.2,0.4,0.6,0.8,1.,1.2,1.4,1.6}
\draw[shift={(\x,0)},color=black] (0pt,2pt) -- (0pt,-2pt);
\draw[->,color=black] (0.,-0.6) -- (0.,1.2);
\foreach \y in {-0.5,-0.4,-0.3,-0.2,-0.1,0.2,0.3,0.4,0.5,0.6,0.7,0.8,0.9,1.,1.1}
\draw[shift={(0,\y)},color=black] (2pt,0pt) -- (-2pt,0pt);
\clip(-0.6,-0.1) rectangle (1.6,1.2);
\draw[smooth,samples=100,domain=-0.6:1.6] plot(\x,{1.0/3.1415926535* rad(atan(10.0*((\x)-0.5)))+0.5});
\draw [dash pattern=on 1pt off 1pt,domain=-0.6:1.6] plot(\x,{(-1.-0.*\x)/-1.});
\draw [->,dash pattern=on 1pt off 1pt] (0.,0.688120318294) -- (0.568235782686,0.690599882462);
\draw [->,dash pattern=on 1pt off 1pt] (0.568235782686,0.690599882462) -- (0.57,0.);
\draw (-0.10792616721,1.20729312763) node[anchor=north west] {$F(x)$};
\draw (-0.0673181324647,0.722300140252) node[anchor=north west] {$U$};
\draw (0.534636264929,0.0039270687237) node[anchor=north west] {$X$};
\draw (1.47339847991,0.0112201963534) node[anchor=north west] {$x$};
\draw (-0.0553745928339,1.01767180926) node[anchor=north west] {$1$};
\end{tikzpicture}
\end{document}
Note. I've add the function rad in front of atan as TikZ uses degrees instead of radians; see the discussion here
Finally, this is the plot I got after compiling the code in LaTex

What is the problem? Am I missing something?


pgfplotsand plot?. However, put,x=4cm,y=4cmand adjust the anchors for nodes. – Jan 16 '15 at 02:10pgfplotsallows you to draw fairly sophisticated plots. – Gonzalo Medina Jan 16 '15 at 02:19pgfplots. I just think its learning curve is steep. – William Zhang Jan 16 '15 at 02:30