Associating two children to one parent in Forest

Question

I am trying to draw a nice multi-dominance. I find the gap between the two lines above "V" is ugly. Is there any way to move the lower end of the line in red square so that the two lines meet at one point right north of "V"?

enter image description here Thank you very much.

\documentclass{article}
\usepackage{forest}

\begin{document}
\begin{forest} where n children=0{tier=CV}{}
    [\sg
    [C, tier=CV]
    [\mo[, tier=CV, no edge][V, name=V, tier=CV]]
    [\mo, name=mo[, no edge, tier=CV]]]
    \draw (mo)--(V);
\end{forest}

\end{document}

Here's a forest solution. Instead of forest, you can also try other methods of drawing such graphs. See this question for example. If you don't mind using pstricks (I do), you can try the pst-asr package. This uses tikz-qtree. You can also directly use the (layered) graph syntax in TikZ. — hftf, Apr 15 '15 at 06:29

score 0 · Accepted Answer · answered Apr 15 '15 at 06:40

\begin{forest} where n children=0{tier=CV}{s sep+=-.5em}
    [\sg
    [C, tier=CV]
    [,phantom]
    [\mo, name=mo1[, tier=CV, no edge]]
    [,phantom[V, name=V, tier=CV]]
    [\mo, name=mo2[, no edge, tier=CV]]]
    \draw (mo1.south)--(V.north);
    \draw (mo2.south)--(V.north);
\end{forest}

I think this works.

Associating two children to one parent in Forest

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