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How can I draw in circuitikz a "circlearrowright" centered in (11,-2) with radium 3cm ? (and what packages I need?) Thank you!

cgnieder
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npatrat
  • 103

1 Answers1

2

Not sure if this is what you intended.

The first coordinate after the \draw command moves the current pen position to the circle's centre. The next coordinate marked by ++() moves the pen relative to current position. Now the arc is drawn from the current pen position with the starting angle, up to the ending angle with a specified radius.

Note that the angle specified in the relative movement must be the same as the starting angle of the arc.

\documentclass[12pt, tikz]{standalone}
\begin{document}
\begin{tikzpicture}[scale=1]
%% below code required only for MWE
\useasboundingbox (7,-6) rectangle (15,2);
\node [fill, circle, inner sep=0pt, minimum size=2pt](mycentre) at (11,-2){};
\node [below of=mycentre] {$(11,-2)$};

%below code is for the circle with arrow
\draw [-latex, thick]
      (11, -2) %centre of the circle
    ++(0:3cm)  %start the arc 'radius'cm away from centre
  arc (0:270:3cm); %arc from 0deg to 270deg with radius
\end{tikzpicture}
\end{document}

circle arrow

AJN
  • 932