8

I have a code like this: (I used the font mtpro2.)

\renewcommand{\arraystretch}{1.6}    
\begin{tabular}{p{8cm}l}
    \multicolumn{2}{l}{(a)~$\left( \frac{81}{16}\right)^{-0.25}\times \left( \frac{8}{27}\right) ^{-\frac{2}{3}}\times (0.25)^{-2.5}+\left(\sqrt{243\sqrt{3}}\right)^{\frac{1}{11}}\times (\sqrt{3})^{-1}=?$} \\
    (b)~$\sqrt[3]{a^{\frac{9}{2}}\sqrt{a^{-3}}}\div \sqrt{\sqrt[3]{a^{-7}}\cdot \sqrt[3]{a}}=?$ & (c)~$(5+2\sqrt{6})^{2000}\cdot (5-2\sqrt{6})^{1999}$ \\
    (d)~$\sqrt[a-b]{x^{\frac{b+c}{c-a}}}\sqrt[b-c]{x^{\frac{c+a}{a-b}}}\sqrt[c-a]{ x^{\frac{a+b}{b-c}}}=?$  &(e)~$(x^{\frac{2}{3}}+x^{-\frac{2}{3}}+1)(x^{\frac{2}{3}}-x^{-\frac{2}{3}})(x-x^{-1})^{-1}=?$
\end{tabular}

enter image description here

How can I make the superscript higher and a little bigger? For example, the orangle part in (d). I've tried throwing \displaystyle in the sub formula in \sqrt{}, but it wasn't lift up much. By the way, I use \renewcommand{\arraystretch}{1.6} to lengthen the lineskip in my tabular environment. Is my method good enough? Is there another proper way to do the same thing?

Eric
  • 1,665

2 Answers2

11

While this approach does not increase the size of the superscript font, it does raise the scripted fraction, by using x\strut^{\frac{b+c}{c-a}} instead of x^{\frac{b+c}{c-a}}, which places the superscript relative to a \strut instead of an x.

\documentclass{article}

\begin{document}
\renewcommand{\arraystretch}{1.6}    
\begin{tabular}{p{8cm}l}
    \multicolumn{2}{l}{(a)~$\left( \frac{81}{16}\right)^{-0.25}\times \left( \frac{8}{27}\right) ^{-\frac{2}{3}}\times (0.25)^{-2.5}+\left(\sqrt{243\sqrt{3}}\right)^{\frac{1}{11}}\times (\sqrt{3})^{-1}=?$} \\
    (b)~$\sqrt[3]{a^{\frac{9}{2}}\sqrt{a^{-3}}}\div \sqrt{\sqrt[3]{a^{-7}}\cdot \sqrt[3]{a}}=?$ & (c)~$(5+2\sqrt{6})^{2000}\cdot (5-2\sqrt{6})^{1999}$ \\
    (d)~$\sqrt[a-b]{x\strut^{\frac{b+c}{c-a}}}\sqrt[b-c]{x\strut^{\frac{c+a}{a-b}}}\sqrt[c-a]{ x\strut^{\frac{a+b}{b-c}}}=?$  &(e)~$(x^{\frac{2}{3}}+x^{-\frac{2}{3}}+1)(x^{\frac{2}{3}}-x^{-\frac{2}{3}})(x-x^{-1})^{-1}=?$
\end{tabular}
\end{document}

enter image description here

For comparison, here it is without the \struts

enter image description here

Steven B. Segletes
  • 237,551
  • Wow. It seems to be what I want. Can you explain more on the mechanism of \strut? I mean what is this command designed for? :) – Eric Mar 31 '17 at 12:38
  • 1
    @Eric \strut (not \struct) is a zero-width entity that vertically spans exactly one complete line height and depth. All normal text will otherwise fit within the vertical footprint of a \strut. If some stacked in-line construction exceeds the height or depth of the \strut, the document line spacing will become irregular, since room must be made to accommodate the extra height/depth. The height plus depth of a \strut equals exactly the value of \baselineskip. – Steven B. Segletes Mar 31 '17 at 12:41
  • @Eric For someghing more visual, a \strut is a zero-width version of this: \rule[-\dp\strutbox]{1pt}{\baselineskip}. Try setting that in a line of text to see it relative to surrounding text. – Steven B. Segletes Mar 31 '17 at 13:18
  • I'm typesetting a Chinese document, so my line spacing is big(I set \linespread{1.6}). When I use \strut in math mode, the exponent part will be lift too up. How can I modify it? (See the middle root in http://imgur.com/a/FsiNi) – Eric Apr 03 '17 at 09:04
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    @Eric you can \newcommand\mystrut{\rule{0pt}{10pt}} and use \mystrut instead of \strut, while varying the height of \mystrut (here chosen as 10pt) to suit your needs. You can add depth to the strut, if needed, with the syntax \rule[<depth>]{0pt}{<height+depth>} – Steven B. Segletes Apr 03 '17 at 10:28
3

How about just x^{^{\frac{b+c}{c-a}}}?

Werner
  • 603,163
Nate
  • 31