(updated the answer to address the OP's follow-up request for a symbol with a tilted crossbar)
Here's a solution that builds on this answer. The names of the user macros are \fiint and \tiltfiint, respectively. In the code shown below, the angle of tilt is set at 15 degrees. Feel free to modify this setting to suit your taste.
If you happen to use a math font symbols package other than (or in addition to) amssymb, the double-integral symbol (\iint) will likely be spaced more tightly than is the case if just amssymb is loaded. If that's the case, simply replace the directive \def\longdash{-\mkern-3.5mu-} in the code below with either \def\longdash{-\mkern-5.5mu-} or -- especially if the esint package is loaded -- \def\longdash{-\mkern-7.5mu-}.

\documentclass{article}
\usepackage{amsmath} % for \iint macro
\usepackage{graphicx} % for \rotatebox macro
\def\Yint#1{\mathchoice
{\YYint\displaystyle\textstyle{#1}}%
{\YYint\textstyle\scriptstyle{#1}}%
{\YYint\scriptstyle\scriptscriptstyle{#1}}%
{\YYint\scriptscriptstyle\scriptscriptstyle{#1}}%
\!\iint}
\def\YYint#1#2#3{{\setbox0=\hbox{$#1{#2#3}{\iint}$}
\vcenter{\hbox{$#2#3$}}\kern-.51\wd0}}
\def\longdash{{-}\mkern-3.5mu{-}}
% consider using "\mkern-7.5mu" if esint package is loaded
\def\tiltlongdash{\rotatebox[origin=c]{15}{$\longdash$}}
\def\fiint{\Yint\longdash}
\def\tiltfiint{\Yint\tiltlongdash}
%\usepackage{esint} %% optional
\begin{document}
$\displaystyle \fiint_u^v f$
\quad
$\fiint_u^v f$
\medskip
$\displaystyle \tiltfiint_u^v f$
\quad
$\tiltfiint_u^v f$
\end{document}
\iintinstead of d. – TeXnician May 10 '17 at 04:31esint) for the\fintmacro? – Mico May 10 '17 at 05:03