This is a bit of a strange one, but I want to be able to base the values of parskip and \parindent on the other (so I can change one and it will change both). I have a way of making them both the same:
\setlength{\parskip}{6pt}
\setlength{\parindent}{\parskip}
But that looks a bit odd. I want to be able to make \parindent a multiple of \parskip. I tried something like:
\setlength{\parskip}{6pt}
\setlength{\parindent}{2*\parskip}
But that didn't work.
Could someone help me please?
2\parskip; but are you really sure you want both paragraph spacing and indent? – egreg May 14 '17 at 11:11\defs, are set at the time of definition, not at the time of invocation. See https://tex.stackexchange.com/questions/123443/defining-a-length-that-scales-with-fontsize-changes – Steven B. Segletes May 14 '17 at 22:47