flowchart drawing problem

Question

I want to draw line from diamond box to start and without individual line from start to four rectangle i want to draw a single branching line from start to sensor data A, sensor data B, sensor data C and sensor data D.

Here is my code:

\tikzset{
decision/.style = {diamond, draw, 
  text width=4.5em, text badly centered, node distance=3cm, inner sep=0pt},
block/.style = {rectangle, draw,  
  text width=5em, text centered, rounded corners, minimum height=4em},
  block2/.style = {rectangle, draw,  
  text width=9em, text centered, rounded corners, minimum height=4em},
line/.style = {draw, -latex'},
cloud/.style = {draw, ellipse, node distance=3cm,
  minimum height=2em},
subroutine/.style = {draw,rectangle split, rectangle split horizontal,
  rectangle split parts=3,minimum height=1cm,
  rectangle split part fill={red!50, green!50, blue!20, yellow!50}},
connector/.style = {draw,circle,node distance=3cm},
data/.style = {draw, trapezium,node distance=3cm}
}
\begin{tikzpicture}[node distance = 2cm, auto]

\node [connector] (start) {Start};
\node [block, below of=start] (B) {sensor data B};
\node [block, left of=B] (A) {sensor data A};
    \node [block, right of=B] (C) {sensor data C};
  \node [block, right of=C] (D) {sensor data D};
  \node [connector,below of=B] (sum) {Sum};
  \node [block2, below of=sum] (read) {Read the sum of sensor data};
  \node [block2, below of=read] (con) {Convert sensor data in percentage};
  \node [decision, below of=con] (decide) {Data $\geq$ 25\%?};

\path [line] (start) -- (A);
\path [line] (start) -- (B);
\path [line] (start) -- (C);
\path [line] (start) -- (D);
\path [line] (A) -- (sum);
\path [line] (B) -- (sum);
\path [line] (C) -- (sum);
\path [line] (D) -- (sum);
\path [line] (sum) -- (read);
 \path [line] (read) -- (con);
 \path [line] (con) -- (decide);

\end{tikzpicture}

Hi, welcome. This is unrelated to your question, but you might want to have a look at https://tex.stackexchange.com/questions/9386/difference-between-right-of-and-right-of-in-pgf-tikz — Torbjørn T., Jun 07 '17 at 11:16

score 1 · Answer 1 · answered Jun 07 '17 at 10:33

For more detail, you may want to look through chapter five, Tutorial: Diagrams as Simple Graphs in the pgf manual; It explains in much more words what to do to achieve the effects you want. You can solve the problems that you have by using edge lines, -| and going around your block D with the calc package. I have changed your code,

\usetikzlibrary{shapes.geometric}
\usetikzlibrary{arrows}
\usetikzlibrary{calc}
\tikzset{
decision/.style = {diamond, draw, 
  text width=4.5em, text badly centered, node distance=3cm, inner sep=0pt},
block/.style = {rectangle, draw,  
  text width=5em, text centered, rounded corners, minimum height=4em},
  block2/.style = {rectangle, draw,  
  text width=9em, text centered, rounded corners, minimum height=4em},
line/.style = {draw, -latex'},
cloud/.style = {draw, ellipse, node distance=3cm,
  minimum height=2em},
subroutine/.style = {draw,rectangle split, rectangle split horizontal,
  rectangle split parts=3,minimum height=1cm,
  rectangle split part fill={red!50, green!50, blue!20, yellow!50}},
connector/.style = {draw,circle,node distance=3cm},
data/.style = {draw, trapezium,node distance=3cm}
}
\begin{tikzpicture}[node distance = 2cm, auto]

\node [connector] (start) {Start};
\node [block, below of=start] (B) {sensor data B};
\node [block, left of=B] (A) {sensor data A};
\node [block, right of=B] (C) {sensor data C};
\node [block, right of=C] (D) {sensor data D};
\node [connector,below of=B] (sum) {Sum};
\node [block2, below of=sum] (read) {Read the sum of sensor data};
\node [block2, below of=read] (con) {Convert sensor data in percentage};
\node [decision, below of=con] (decide) {Data $\geq$ 25\%?};

\path [line] (start.south) -| (A);
\path [line] (start.south) -| (B);
\path [line] (start.south) -| (C);
\path [line] (start.south) -| (D);
\path [line] (A) -- (sum);
\path [line] (B) -- (sum);
\path [line] (C) -- (sum);
\path [line] (D) -- (sum);
\path [line] (sum) -- (read);
\path [line] (read) -- (con);
\path [line] (con) -- (decide);
\path[line] (decide) -| ($(D.east) + (1cm,0)$) |- (start);

\end{tikzpicture}

I hope this helps you on your quest. The path back to the beginning goes via D to avoid changing it again if you re-arrange your drawing. If you add more blocks, you may have to change D.east to reflect that.

flowchart drawing problem

1 Answers1