The following code renders a sphere and a plane. How do I get the plane to be at the south pole of the sphere - and centered? On this diagram, I would like to draw a ray from the north pole N through the point P = (-\sqrt{3}, -1/\sqrt{2},-1/\sqrt{2}) and through the point Q = ((-\sqrt{3}/7)(-8+2\sqrt{2}), (-\sqrt{2}/14)(-8+2\sqrt{2}), -2) of intersection between the ray and the plane, and I would like to mark N, P, and Q with a dot. (I want to keep the code in a TikZ environment.)
\documentclass{amsart}
\usepackage{mathtools,array}
\usepackage{tikz}
\usetikzlibrary{calc,intersections}
\begin{document}
\begin{center}
\begin{tikzpicture}
\shade[ball color=blue!25] (0,0,0) circle (2);
\fill[opacity=0.25] (-3,0,4) -- (-1,2,4) -- (5,2,4) -- (3,0,4) -- cycle;
\end{tikzpicture}
\end{center}
\end{document}
\fill[opacity=0.25] (-2,-2,-2) -- (2,-2,-2) -- (2,-2,2) -- (-2,-2,2) -- cycle; \shade[ball color=blue!25] (0,0,0) circle (2);should get you going. – Huang_d Oct 26 '17 at 16:18TeXcommands. I know that to code inTikZ, the coordinates would be specified with commands likesqrt(3)and-1/sqrt(2). – user74973 Oct 29 '17 at 17:46y-axiscomes out of the paper. Suppose I simply want to draw the liney=2xon the planez=0. How would that be drawn? Typically, the perspective for such drawings is off they-axisso that thex-axisandy-axisare not perpendicular to each other. – user74973 Oct 29 '17 at 17:52