The simplest way to fill a matrix of nodes?

Question

Code:

           \tikzstyle{matrici}=[
       matrix of math nodes, 
      nodes in empty cells,
      column sep=-\pgflinewidth, % to avoid double borders in contiguous cells
   nodes={
    draw, 
   align=center, 
  inner sep=0pt, 
    text width=1cm, 
    minimum height=1cm
}
]

               \begin{tikzpicture} 
\matrix[matrici, 
column 1/.style={nodes={fill=blue!10}},  
column 2/.style={nodes={fill=blue!10}},
column 3/.style={nodes={fill=blue!10}},
column 4/.style={nodes={fill=blue!10}},
]  (X)  {&&&&&&&\\};
\end{tikzpicture}

output:

there is no way ti fill the first 4 cells with a "cicle for"? Im forced to write this?

   column 1/.style={nodes={fill=blue!10}},  
    column 2/.style={nodes={fill=blue!10}},
   column 3/.style={nodes={fill=blue!10}},
     column 4/.style={nodes={fill=blue!10}},

it will be fine somethig like

   \foreach \x in {1,2,3,4} 
   fill the node (X-1-\x) with this color

You can define a style with column number as parameter and define a .list which will use it. More clear at https://tex.stackexchange.com/questions/175616/tikz-matrix-style-for-combination-or-rows-and-columns — Ignasi, Dec 28 '17 at 19:14
if you define mycols/.style={column #1/.style={nodes={fill=blue!10}} then you can call it with mycols/.list={1,...,4} — percusse, Dec 29 '17 at 10:00
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Torbjørn T. · Answer 1 · 2017-12-28T17:34:17.300

You can do add a \fill to the background layer:

\documentclass[border=5mm]{standalone}
\usepackage{tikz}
\usetikzlibrary{matrix,backgrounds}
\tikzset{ % \tikzstyle is considered deprecated
  matrici/.style={
    matrix of math nodes, 
    nodes in empty cells,
    column sep=-\pgflinewidth, % to avoid double borders in contiguous cells
    nodes={
      draw, 
      align=center, 
      inner sep=0pt, 
      text width=1cm, 
      minimum height=1cm
    }
  }
}

\begin{document}
\begin{tikzpicture} 
\matrix[matrici]  (X)  {&&&&&&&\\};

\begin{scope}[on background layer]
\foreach \x in {1,...,4}
  \fill [blue!10] (X-1-\x.south west) rectangle (X-1-\x.north east);
\end{scope}
\end{tikzpicture}   

\end{document}

Another option is to do something similar to what Loop Space did in his answer to How can I set the background color of the rows and columns of a matrix node in Tikz?:

\documentclass[border=5mm]{standalone}
\usepackage{tikz}
\usetikzlibrary{matrix,backgrounds}
\tikzset{
  matrici/.style={
    matrix of math nodes, 
    nodes in empty cells,
    column sep=-\pgflinewidth, % to avoid double borders in contiguous cells
    nodes={
      draw, 
      align=center, 
      inner sep=0pt, 
      text width=1cm, 
      minimum height=1cm
    }
  }
}

\begin{document}
\begin{tikzpicture} 
\matrix[
  matrici,
  nodes={
   execute at begin node={
       \pgfmathparse{\pgfmatrixcurrentcolumn<5 ? "blue!10" : "white"}
        \xglobal\colorlet{nodebg}{\pgfmathresult}},
        preaction={fill=nodebg}
}
]  (X)  {&&&&&&&\\};


\end{tikzpicture}   
\end{document}

score 2 · Answer 2 · answered Dec 28 '17 at 22:11

Pardon my ignorance of understanding your question but if you are looking for creating a colored box then you can do the following (i.e. please correct me if I misunderstood your question because it is not totally clear to me).

\documentclass[border={10pt}]{standalone}
\usepackage{tikz}

\begin{document}
\begin{tikzpicture}
    [%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
        colorbox/.style={rectangle,fill=blue!10,draw=black,thick, minimum size=1cm},
        box/.style={rectangle,draw=black,thick, minimum size=1cm},
    ]%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

\foreach \x in {0,...,3}
    \node[colorbox] at (\x,0){};

\foreach \x in {4,...,7}
    \node[box] at (\x,0){};

\end{tikzpicture}
\end{document}

The simplest way to fill a matrix of nodes?

2 Answers2

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