it's not clear what you mean with "in a good position" ...
one solution using split can be:

\begin{equation}
\begin{split}
& \frac{r(r-1)c_{0}}{z} + \sum_{0}^{\infty}\Bigl[(j+r)(j+r+1)c_{j+1} \\
&\qquad - [(j+r)(j+r-1) - l(l+1)]c_{j}\Bigr] = 0,
\end{split}
\end{equation}
addedndum:
solution as you like to have:
\documentclass{article}
\usepackage{mamsmath}
\begin{document}
\begin{equation}
\begin{split}
& \frac{r(r-1)c_{0}}{z} + \sum_{0}^{\infty}\Bigl[(j+r)(j+r+1)c_{j+1} \\
& - [(j+r)(j+r-1) - l(l+1)]c_{j}\Bigr] = 0,
\end{split}
\end{equation}
\end{document}

another solution (which I like the most) is with use of the package mathtools and its environment multlined:
\documentclass{article}
\usepackage{mathtools}
\begin{document}
\begin{equation}
\begin{multlined}[0.7\linewidth]
\frac{r(r-1)c_{0}}{z} + \sum_{0}^{\infty}\Bigl[(j+r)(j+r+1)c_{j+1} \\
- [(j+r)(j+r-1) - l(l+1)]c_{j}\Bigr] = 0,
\end{multlined}
\end{equation}
\end{document}

\documentclass{...}and ending with\end{document}. it is not fun to write from scratch missing part of code (which can be also essential), especially you already have this code ... (ii) welcome to tex.se! – Zarko Mar 22 '18 at 16:18