glossaries: one entry for every symbol without derivatives

Question

I have created a symbol-list with the glossaries package and so far everything worked great. Now, I have to write an equation which includes the derivative of one entry. The derivative is shown by a dot over the symbol. I would like to just do something like: \dot{\gls{...}} but this obviously doesn't account for the indices and prints the dot over the middle.

I can just include the derivative in the glossary, but this has some disadvantages:

If only the derivative is referenced, the glossary will not include the normal symbol.
If I have multiple derivatives the glossary gets crowded.
The derivatives have often no "real" meaning, like a=\dot{v}=\ddot{x}

Unfortunately, I can't just use the \prime operator to show the derivatives, because this is already used to show a transformation.

How can I archive a glossary like that?

Here is one of my entries, maybe it helps:

\newglossaryentry{form:komplstatorwiderstand}{
    name=\ensuremath{\uline{Z}_\mathrm{S}},
    description={Statorwiderstand},
    sort=ZS, 
    type=symbolslist
}

Perhaps something like Symbols with optional parameter in glossaries with \newglossary. — Nicola Talbot, Nov 21 '18 at 17:44

score 1 · Accepted Answer · answered Nov 23 '18 at 13:47

You can use the extra fields in the glossaries package: user1, user2, user3, and so on. You call them by using \glsuseri, \glsuserii, \glsuseriii and so on (using roman numerals).

example:

\documentclass{article}
\usepackage{glossaries}

\newglossaryentry{ex}{
    name=\ensuremath{X_\mathrm{S}},
    description={Statorwiderstand},
    sort=ZS, 
    user1 =\ensuremath{\dot{X}_\mathrm{S}}
}

\begin{document}
   Testing the normal \gls{ex} and now with dot \glsuseri{ex}
\end{document}

glossaries: one entry for every symbol without derivatives

1 Answers1