2

I am trying to replicate this formula with LaTeX:

enter image description here

However, I am struggling to make the fraction look the same. This is my attempt:

\begin{equation}

\label{eq:alphaK}

\alpha(k) = \frac{1}{(N-k)} \nicefrac{ \left( \displaystyle \sum_{i=k+1}^{N} \lambda_i \right) }{\left( \displaystyle \prod_{i=k+1}^N \lambda_i \right)^{\frac{1}{N-k}}}

\end{equation}

Which results in the following:

enter image description here

I am looking for a way to increase the size of the "slash" (/) that separates the numerator and denominator. I know I could use a normal \frac instead of \nicefrac but I like how it looks when num/den are displayed side by side.

Is there any way I can force the fraction to look more like the first pictured one?

andselisk
  • 2,675
  • 1
    welcome to tex.se! please, always provide complete small document (beginning with \documentclass followed by necessary preamble and ending with \end{document}). – Zarko Dec 12 '18 at 16:50
  • 1
    My apologies, I will do so in future – David Scott Dec 12 '18 at 17:10

2 Answers2

7

There are many ways. You will find two different in some variation below. The last one looks more like your desired output.

\documentclass{memoir}
\usepackage{amsmath,xfrac,mathtools}

\begin{document} \begin{align} \alpha(k) &=\frac{1}{(N-k)} \left. \left(\sum_{i=k+1}^{N} \lambda_i \right) \right/ \left(\prod_{i=k+1}^N \lambda_i \right)^{\sfrac 1{(N-k)}}\label{eq:alphaK}\ &=\frac{1}{N-k} \left. \left(\sum_{i=k+1}^{N} \lambda_i \right) \middle/ \left(\prod_{i=k+1}^N \lambda_i \right)^{\frac 1{N-k}} \right.\ &=\frac{1}{N-k} \biggl(,\sum_{i=k+1}^{N} \lambda_i \biggr) \bigg/ \biggl(,\prod_{i=k+1}^N \lambda_i \biggr)^{1/{(N-k)}}\ %space added as suggested by Enrico Gregorio &=\frac {\sum\limits_{i=k+1}^{N} \lambda_i} {(N-k), \sqrt[N-k]{\prod\limits_{i=k+1}^N\lambda_i}} &\geq 1 \textup{ (by the AM–GM inequality)} \end{align} \end{document}

enter image description here


Remarks.

CampanIgnis
  • 4,624
4

a small variation of CampanIgnis answer (since he was to fast for my frozen fingers :-( ):

\documentclass{article}
\usepackage{nccmath}

\begin{document}
\begin{equation}%\label{eq:alphaK}
\alpha(k) = \frac{1}{(N-k)}
            \left(\sum_{i=k+1}^{N} \lambda_i \middle)
            \!\middle/\!
            \middle(\prod_{i=k+1}^N \lambda_i \right)^{\mfrac{1}{N-k}}
\end{equation}
\end{document}

enter image description here

Zarko
  • 296,517
  • Very nice :-)...for the frozen fingers. – Sebastiano Dec 12 '18 at 21:15
  • @Zarko I then recommend you some お茶 for your fingers. – CampanIgnis Dec 12 '18 at 23:13
  • @Zarko I have a general question on your solution: If one of the products would be much, much larger then all other three delimiters would grow, too. Is that intentional? – CampanIgnis Dec 12 '18 at 23:20
  • 1
    @CampanIgnis, oh, it would be sufficient if I had a warm glove on my afternoon the walk :-). about size of nominator and donominator: size is slašš line depends on taste. in such cases will rather use the following aproach: \left(<nominator>\right)\left(<denominator>\right)^{-1} – Zarko Dec 12 '18 at 23:34