How to remove the unexpected vertical space in the theorem environment?

Question

When I use \pause in \[ \] formula in the theorem environment, I get an unexpected extra space below the formula; see Theorem: Pause (formula). Now I remove it using \vspace{-0.60}cm, as in Theorem: Pause and Negative VSpace.

How to remove it without using \vspace?

\documentclass[beamer]{standalone}
\usetheme{CambridgeUS}

\begin{document}
\begin{frame}
  \begin{theorem}[No Pause]
    \[
      a + b = c
    \]
  \end{theorem}

  \begin{theorem}[Pause (formula)]
    \[
      a + b = \pause c
    \]
  \end{theorem}

  \begin{theorem}[Pause and Negative VSpace]
    \[
      a + b = \pause c
    \]
    \vspace{-0.60cm}
  \end{theorem}

  \begin{theorem}[Pause (text)]
    a + b = \pause c
  \end{theorem}
\end{frame}
\end{document}

Does https://tex.stackexchange.com/q/41509/15925 help? (There are two different answers). — Andrew Swann, Apr 07 '19 at 07:51
@AndrewSwann Yes, thanks. However, I like the solution given by David Carlisle below. — hengxin, Apr 08 '19 at 02:02

score 3 · Accepted Answer · answered Apr 07 '19 at 09:12

I haven't traced fully and I'm not sure it's completely robust in all cases but you can keep the pause mechanics within the formula, so avoid starting a line after the display, by adding a group

\documentclass[beamer]{standalone}
\usetheme{CambridgeUS}

\begin{document}
\begin{frame}
  \begin{theorem}[No Pause]
    \[
      a + b = c
    \]
  \end{theorem}

  \begin{theorem}[Pause (formula)]
    \[
      {a + b = \pause c}
    \]
  \end{theorem}

  \begin{theorem}[Pause and Negative VSpace]
    \[
      a + b = \pause c
    \]
    \vspace{-0.60cm}
  \end{theorem}

  \begin{theorem}[Pause (text)]
    a + b = \pause c
  \end{theorem}
\end{frame}
\end{document}

+1 Writing {\pause} also works and doesn't freeze the spacing in the formula. — Andrew Swann, Apr 08 '19 at 07:40

How to remove the unexpected vertical space in the theorem environment?

1 Answers1