I need to get rid of that.10^-3 and instead show the actual number, i.e. 0.003:

How can I do that? I also would like to use the style of the markers that you see in this picture:
CODE:
\documentclass{book}
\usepackage{multirow}
\usepackage{color}
\usepackage{layout}
\usepackage{subcaption}
\usepackage{caption}
\usepackage{tikz}
\usepackage{pgfplots}
\pgfplotsset{compat=1.16}
%\pgfplotsset{}
\usetikzlibrary{decorations.pathreplacing}
\begin{document}
\begin{figure}
\begin{subfigure}[b]{0.5\textwidth}
\begin{tikzpicture}
\begin{axis}[
width=\linewidth,
line width=0.5,
grid=major, % Display a grid
tick label style={font={\tiny }},
legend style={nodes={scale=0.6, transform shape}},
label style={font={\tiny }},
legend image post style={},
grid style={white},
xlabel={$\gamma{1}$},
ylabel={RMSE},
y tick label style={
/pgf/number format/.cd,
fixed,
fixed zerofill,
precision=2
},
legend style={at={(1,0.75)}, anchor=north east, draw=none, fill=none},
]
\addplot[mark=oplus*,blue] coordinates
{(0.00,1.1257) (0.001, 0.9556) (0.002,0.9449) (0.003,0.9415) (0.004,0.9399)(0.005, 0.9398) (0.006,0.9396) (0.007,0.9397) (0.008,0.9398)
};
\addlegendentry{Error }
% \addplot[mark=*,black] coordinates
% { (2, 0.9174) (4,0.8977) (6,0.8845) (8,0.8803) (10,0.8683)(12, 0.8606) (14, 0.8524) (16,0.8460) (18,0.8391) (20,0.8326) (22,0.8262) (24,0.8199) (26,0.8141)
% (28,0.8093)(30,0.8018)(32,0.7987)(34,0.7924)(36,0.7874)(38,0.7819) (40,0.7775)(42,0.7724)(44,0.7674)(46,0.7630) (48,0.7584) (50,0.7543)
% };
% \addlegendentry{$\gamma{1}$}
\end{axis}
\end{tikzpicture}
\subcaption{blabla}
\label{sub111}
\end{subfigure}
\begin{subfigure}[b]{0.5\textwidth}
\begin{tikzpicture}
\begin{axis}[
width=\linewidth,
line width=0.5,
grid=major, % Display a grid
tick label style={font={\tiny}},
legend style={nodes={scale=0.6, transform shape}},
label style={font={\tiny }},
legend image post style={},
grid style={white},
xlabel={ $\lambda_{1}$},
ylabel={RMSE},
y tick label style={
/pgf/number format/.cd,
fixed,
fixed zerofill,
precision=2
},
legend style={at={(0.5,0.75)}, anchor=south east, draw=none, fill=none},
]
\addplot[mark=oplus*,blue] coordinates
{(0.00,0.9397) (0.001, 0.9394) (0.002,0.9399) (0.003,0.9402) (0.004,0.9399)(0.005, 0.9400) (0.006,0.9406) (0.007,0.9405) (0.008,0.9408)
};
\addlegendentry{Error}
% \addplot[mark=*,black] coordinates
% { (2, 0.8780) (4,0.8569) (6,0.8428) (8,0.8326) (10,0.8249)(12, 0.8175) (14, 0.8114) (16,0.8063) (18,0.8010) (20,0.7950) (22,0.7909) (24,0.7860) (26,0.7821)
% (28,0.7780)(30,0.7737)(32,0.7700)(34,0.7655)(36,0.7615)(38,0.7587) (40,0.7548)(42,0.7510)(44,0.7481)(46,0.7442) (48,0.7405) (50,0.7372)
%
% };
% \addlegendentry{}
\end{axis}
\end{tikzpicture}
\subcaption{Blabla}
\end{subfigure}
\caption{Performance}
\label{tablex1}
\end{figure}
\end{document}

xinstead ofy). Andmark=o. – Torbjørn T. May 30 '19 at 07:44x tick label style={/pgf/number format/.cd,fixed,fixed zerofill,precision=4},– May 30 '19 at 07:46scaled x ticks=false, as mentioned in the first line of Jake's answer. – Torbjørn T. May 30 '19 at 07:48