I have the following equation:
\documentclass{amsbook}
\usepackage[frenchstyle]{kpfonts}
\DeclarePairedDelimiter{\abs}{\lvert}{\rvert}
\begin{document}
\[
\abs[\Big]{\varint f(x)\D{x}}
= \lim_{k\to +\infty} \abs[\Big]{\varint f_k(x) \D{x}}
\leqslant \lim_{k\to +\infty} \int\abs{f_k(x)} \D{x}
= \int\abs{f(x)}\D{x}
\]
\end{document}
which I spaced as follows, by sheer trial and error until I got something aesthetically pleasing:
\[
\abs[\Big]{\varint f(x)\D{x}\;}\;\: % <-- Pure empirical spacing
= \lim_{k\to +\infty} \abs[\Big]{\varint f_k(x) \D{x}\;}\;\: % <--
\leqslant \lim_{k\to +\infty} \int\abs{f_k(x)} \D{x}\; % <--
= \int\abs{f(x)}\D{x}.
\]
As you can appreciate, for each binary relation I tried to leftwards get the same amount of blank space produced rightwards by either the long subscripts of the limit operators or by the integral symbol, as well as to center the body of the integrals within the absolute value.
My questions are:
- Am I adding too much, superfluous, blank space? If so,
- What would be a better, more austere solution?
- Is there an intrinsic way to measure and reproduce the distance between
=or\leqslantto the l of\limor the midpoint of\intto the right?
I already discarded to use \smashoperator from mathtools.



alignfor equation environment and break the equation manually at the point of my preference. – hesham Jun 09 '20 at 17:30! Undefined control sequence. <recently read> \DeclarePairedDelimiter– David Carlisle Jun 09 '20 at 20:05