TikZ: different rounded-corner radii of a horizontal-vertical path with two turns

Question

I would like to draw a horizontal-vertical path between two nodes, with different radii of rounded corners.

Here's my original code (single-radius):

\documentclass[tikz]{standalone}
\usetikzlibrary{fit,arrows.meta,mindmap,shadows,backgrounds,calc,positioning,shapes.misc}
\tikzset{Arrow/.style={-{stealth},very thick}}
\begin{document}
\begin{tikzpicture} [every node/.style={draw,rectangle,rounded corners,minimum width=22mm},
    every text node part/.style={align=center}]
\node (A) at (0,0) {A};
\node (B) at (5,5) {B};
\draw[Arrow,rounded corners=5pt]
    % start at source
    (A)
    % go right and up to anchor
    -| ($ (B.south) - (18.5mm,3mm) $)
    % go right and up to target
    -| ([xshift=-7mm]B.south)
    ;
\end{tikzpicture}
\end{document}

Results:

Now I would like the first turn to have a larger radius. The expected results should look like the following (please ignore the imperfections due to my bad GIMP skills):

I followed this answer to set a different radius for the first turn:

\documentclass[tikz]{standalone}
\usetikzlibrary{fit,arrows.meta,mindmap,shadows,backgrounds,calc,positioning,shapes.misc}
\tikzset{Arrow/.style={-{stealth},very thick}}
\begin{document}
\begin{tikzpicture} [every node/.style={draw,rectangle,rounded corners,minimum width=22mm},
    every text node part/.style={align=center}]
\node (A) at (0,0) {A};
\node (B) at (5,5) {B};
\draw[Arrow,rounded corners=5pt]
    % start at source
    (A)
    % go right and up to anchor
        { [rounded corners=30pt]
        -| ($ (B.south) - (18.5mm,3mm) $)
        }
    % go right and up to target
    -| ([xshift=-7mm]B.south)
    ;
\end{tikzpicture}
\end{document}

Results are not as expected:

Thank you very much in advance for your help!

John Kormylo · Accepted Answer · 2020-07-01T22:08:10.757

2

You have three turns, but only two are explicit. TikZ intuits the third.

\documentclass[tikz]{standalone}
\usetikzlibrary{fit,arrows.meta,mindmap,shadows,backgrounds,calc,positioning,shapes.misc}
\tikzset{Arrow/.style={-{stealth},very thick}}
\begin{document}
\begin{tikzpicture} [every node/.style={draw,rectangle,minimum width=22mm},
    every text node part/.style={align=center}]
\node (A) at (0,0) {A};
\node (B) at (5,5) {B};
\draw[Arrow,rounded corners=30pt]
    % start at source
    (A)
    % go right and up to midpoint
    -| ($ (B.south) - (18.5mm,2.5) $)
    % got up and right to the anchor
    [rounded corners=5pt]
    |- ($ (B.south) - (12mm,3mm) $)
    % go right and up to target
    -| ([xshift=-7mm]B.south)
    ;
\end{tikzpicture}
\end{document}

This version uses corners instead of midpoints.

\documentclass[tikz]{standalone}
\usetikzlibrary{fit,arrows.meta,mindmap,shadows,backgrounds,calc,positioning,shapes.misc}
\tikzset{Arrow/.style={-{stealth},very thick}}
\begin{document}
\begin{tikzpicture} [every node/.style={draw,rectangle,minimum width=22mm},
    every text node part/.style={align=center}]
\node (A) at (0,0) {A};
\node (B) at (5,5) {B};
\coordinate (AB) at ($ (B.south) - (18.5mm,3mm) $); % for simplicity
\coordinate (BB) at ([xshift=-7mm]B.south);
\draw[Arrow,rounded corners=30pt]
    % start at source
    (A) -- (A -| AB) % first corner
    [rounded corners=5pt]
     -- (AB) -- (AB -| BB) -- (BB);
\end{tikzpicture}
\end{document}

edited Jul 01 '20 at 22:08

answered Jul 01 '20 at 12:56

John Kormylo

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Woah, why didn't I think about this before? Perfect answer! Thank you very much! – f10w Jul 01 '20 at 13:32
Unfortunately this solution is not generic :( I changed the second to to \node (B) at (5,2.5) {B}; and couldn't find parameters that give an acceptable result :( Could you please have a look? – f10w Jul 01 '20 at 14:20
To find a midpoint, add the coordinates of the corners and divide by 2, or use (A!0.5!B) (calc tikzlibrary). – John Kormylo Jul 01 '20 at 22:11
Works perfectly! Thank you so much! – f10w Jul 03 '20 at 00:47
Oops, make that ($(A)!0.5!(B)$). – John Kormylo Jul 03 '20 at 00:52
I used your second version so I didn't try the midpoint :D – f10w Jul 03 '20 at 00:53
I've just tried midpoint but the results are bad (there's an extra line). Your second solution is excellent though. – f10w Jul 03 '20 at 00:57
Remember, this is for posterity. – John Kormylo Jul 03 '20 at 01:07
Sure, you are right. Thank you again! – f10w Jul 03 '20 at 01:08

TikZ: different rounded-corner radii of a horizontal-vertical path with two turns

1 Answers1