I type in the code shown below for a displayed formula. However the output is not what it should be. Can you tell me what is the mistake over here?
$$ \frac{(1-a)\frac{$q_{f}$}{{$q_{n}$}^a}}{$p_{n}$} \cdot $q_{f}$ \cdot $\Delta p$ $$
I type in the code shown below for a displayed formula. However the output is not what it should be. Can you tell me what is the mistake over here?
$$ \frac{(1-a)\frac{$q_{f}$}{{$q_{n}$}^a}}{$p_{n}$} \cdot $q_{f}$ \cdot $\Delta p$ $$
First of All, You can't nest $ in $$. Therefore your formula should be like
$$ \frac{(1-a)\frac{q_{f}}{{q_{n}}^a}}{p_{n}} \cdot q_{f} \cdot \Delta p $$
Building on Hassan Zakeri's answer, you have two potential problems. As Hassan says, you can't nest.
But it is also much better not to use $$ to start display maths. Here's a better solution:
\[ \frac{(1-a)\frac{q_{f}}{{q_{n}}^a}}{p_{n}} \cdot q_{f} \cdot \Delta p \]
For further explanation, please read this question and its answers: Why is [ … ] preferable to $$?