Controlling the scope of a \savebox\strutbox{$\vphantom{}$} statement

Question

I was looking for the same solution to the problem explained by the OP in this question: How to make formulae take equal vertical space in the align environment?. I have implemented the solution suggested in user2478's answer.

However, one issue I am having is that my document is long, and I have the impression that when using the line of code \savebox\strutbox{$\vphantom{}$}, the effect carries on indefinitely until the end of the document or the next similar statement. I would need to be able to specify the scope of this statement.

I left a comment in that answer 5 days ago, unfortunately the original answerer seems to have no longer a StackExchange account, and I have not received any reply since then.

How can I control the scope of the above statement?

David Carlisle · Answer 1 · 2020-10-10T13:55:16.357

1

\savebox is a local assignment like \newcommand and is scoped to the current group or environment, like a font change or command definition.

edited Oct 10 '20 at 13:55

answered Oct 10 '20 at 12:48

David Carlisle

757,742

Thank you, I should have tested this before asking actually... – Daneel Olivaw Oct 10 '20 at 13:07

score 1 · Accepted Answer · answered Oct 10 '20 at 12:49

Since \savebox does a local box assignment, you can simply use it inside a TeX group:

\documentclass{article}
\usepackage{amsmath}
\begin{document}
{%
  \savebox\strutbox{$\vphantom{\dfrac11}$}%
  % or equivalently:
  % \sbox{\strutbox}{$\vphantom{\dfrac{1}{1}}$}%
  \begin{align}
    f_1(x) &= \frac{15x}{3} \
    f_2(x) &= 3x + 5 \
    f_3(x) &= 4x + 13
  \end{align}
}
\begin{align}
  f_1(x) &= \frac{15x}{3} \
  f_2(x) &= 3x + 5 \
  f_3(x) &= 4x + 13
\end{align}
\end{document}

(David Carlisle was a bit faster...).

Thank you, this provides a visual example that it is working. — Daneel Olivaw, Oct 10 '20 at 13:06

Controlling the scope of a \savebox\strutbox{$\vphantom{}$} statement

2 Answers2