I am trying to draw a circular linked list that looks similar to the one in this question How to draw a circular linked list.
The difference is that I want the nodes arranged around a circle, which I have successfully done with the code below:
\begin{center}
\begin{tikzpicture}[scale=2.5,list/.style={
rectangle split,
rectangle split parts=2,
rectangle split horizontal,
rectangle split part fill={red!30,blue!20},
rounded corners,
draw=black, thick,
minimum height=0.65cm,
text width=1cm,
text centered,
}]
\node [list] at (0 * 360/6: 1.5) (A) {$\bullet$ \nodepart{two} \texttt{Head}};
\node [list] at (1 * 360/6: 1.5) (B) {$\bullet$ \nodepart{two} \texttt{B}};
\node [list] at (2 * 360/6: 1.5) (C) {$\bullet$ \nodepart{two} \texttt{C}};
\node [list] at (3 * 360/6: 1.5) (D) {\texttt{D} \nodepart{two} $\bullet$};
\node [list] at (4 * 360/6: 1.5) (E) {\texttt{E} \nodepart{two} $\bullet$};
\node [list] at (5 * 360/6: 1.5) (F) {\texttt{F} \nodepart{two} $\bullet$};
\draw[->] let \p1 = (A.one), \p2 = (A.two) in [bend right] (\x1,\y2) [bend right] to (B.two);
\draw[->] let \p1 = (B.one), \p2 = (B.center) in (\x1,\y2) [bend right] to (C);
\draw[->] let \p1 = (C.one), \p2 = (C.center) in (\x1,\y2) [bend right] to (D.one);
\draw[->] let \p1 = (D.two), \p2 = (D.center) in (\x1,\y2) [bend left] to (E.one);
\draw[->] let \p1 = (E.two), \p2 = (E.center) in (\x1,\y2) [bend left] to (F.one);
\draw[->] let \p1 = (F.two), \p2 = (F.center) in (\x1,\y2) [bend right] to (A.one);
\end{tikzpicture}
\end{center}
What I've failed to do is connect the nodes from the bullets, that are in the middle of one of the split rectangles, to the center following node's value's center. See the image below:


($(A.west)!0.25!(A.east)$)for example. (This must be some new definition of linked list I had not been previously aware of.) – John Kormylo Oct 10 '20 at 22:19