Putting a matrix just beside a graph

Question

\documentclass[a4paper,12pt,twoside]{report}
\usetikzlibrary{decorations.markings}
\begin{document}
 \begin{figure}[hbt!]
    \begin{center}
    \begin{tikzpicture}[scale=0.95,
                thick,
                acteur/.style={
                    circle,
                    fill=black,
                    thick,
                    inner sep=2pt,
                    minimum size=0.2cm,scale=0.65
                }
                ] 
                \node (a1) at (0,0) [acteur,label=left:\footnotesize{1}]{}; 
                \node (a2) at (1.5,0)  [acteur,label=right:\footnotesize{2}]{};           
                \node (a3) at (1.5,1.5) [acteur,label=right:\footnotesize{3}]{};     
                \node (a4) at (0,1.5) [acteur,label=left:\footnotesize{4}]{};         
                \node (a5) at (.75,3) [acteur,label=above:\footnotesize{5}]{};                
                \draw [green, decoration={markings, mark=at position 0.5 with {\arrow{>}}}, postaction={decorate}]  (a1) -- (a2); 
                \draw  [blue](a2) -- (a3); 
                \draw [green, decoration={markings, mark=at position 0.5 with {\arrow{>}}}, postaction={decorate}]  (a3) -- (a4);
                \draw  [red](a4) -- (a1);
                \draw [blue] (a4) -- (a5);
                \draw [red]  (a5) -- (a3);
                A(G)=
  \left[ {\begin{array}{rrrrr}
   0 & \mathrm{i} & 0 & 1 & 0 \\
   -\mathrm{i} & 0 & -1 &0 &0 \\
   0 & -1 & 0 & \mathrm{i} & 1\\
   1 & 0 & -\mathrm{i} &0 & -1\\
   0 & 0 &1 &-1 &0
  \end{array} } \right]
            \end{tikzpicture}




          \caption{ $G, A(G)$}\label{F2}
          \end{center}
    \end{figure}
\end{document}

Here I want to put the matrix just in the right of the graph. How to do that?

Please make your code compilable and format your question, so that your text is not part of your code. -use the format buttons at the top. — hpekristiansen, Jun 25 '21 at 11:05
This question by @rugtyi789 had the same code and the same question format problem: https://tex.stackexchange.com/questions/602618/drawing-arrows-in-the-following-latex-picture - Are there any reason to have multiple accounts here? — hpekristiansen, Jun 25 '21 at 11:10
@hpekristiansen It's possible there are two separate students copying the same wrong answer from the darkTeX-web in an effort to answer the same homework problem. LOL!! — Steven B. Segletes, Jun 25 '21 at 12:01
@StevenB.Segletes: Yes it is possible. This question have my solution from the other question included (part one of an exercise?). -and ask for an other thing(part two?). Both questions were/are formatted strange with text at bottom formatted as part of the code. Anyway - there is nothing wrong by itself of having multiple accounts. Both behaviours are suspect in my opinion. -let us hope the teacher also knows about this site. — hpekristiansen, Jun 25 '21 at 12:13
Please consider accepting one of the provided answers. This is true for almost all of your previous questions. — Dr. Manuel Kuehner, Jul 26 '21 at 08:08

score 2 · Answer 1 · answered Jul 26 '21 at 07:38

You can (should) write your matrix outside of image:

I took a liberty and quite rewrite the code of the your image (with goal to be simpler):

\documentclass[a4paper,12pt,twoside]{report}
\usepackage{mathtools}  % new
\usepackage{tikz}
\usetikzlibrary{decorations.markings}
\begin{document}
\begin{figure}[hbt!]
    \centering
    \begin{tikzpicture}[baseline=(a3.south),
acteur/.style = {circle, draw, fill, inner sep=2pt,
                 node contents={}},
   ->-/.style = {decoration={markings, mark=at position 0.5 with {\arrow{>}}},
                 draw=#1, 
                 postaction={decorate}},

every label/.append style = {font=\footnotesize},
 every path/.append style = semithick
                ]
\node (a1)              [acteur,label=left:1];
\node (a2) at (1.5,0.0) [acteur,label=right:2];
\node (a3) at (1.5,1.5) [acteur,label=right:3];
\node (a4) at (0.0,1.5) [acteur,label=left:4];
\node (a5) at (.75,3.0) [acteur,label=5];
%
\draw [->- = green]  (a1) -- (a2);
\draw [blue] (a2) -- (a3);
\draw [->- = blue]   (a3) -- (a4);
\draw [red]  (a4) -- (a1);
\draw [blue] (a4) -- (a5);
\draw [red]  (a5) -- (a3);
   \end{tikzpicture}
\qquad
$A(G)= \begin{bmatrix}[r]
    0   &  i &  0 &  1 &  0 \
   -i   &  0 & -1 &  0 &  0 \
   0    & -1 &  0 &  i &  1 \
   1    &  0 &  i &  0 & -1 \
   0    &  0 &  1 & -1 &  0
    \end{bmatrix}$
\caption{ $G, A(G)$}\label{Fd2}
    \end{figure}
\end{document}

+1: Nice and clean. But I would have a look at the OP's comments below before helping again in the future. — Dr. Manuel Kuehner, Jul 26 '21 at 08:13

score -1 · Answer 2 · answered Jun 26 '21 at 06:07

\documentclass[a4paper,12pt,twoside]{report}
\usetikzlibrary{decorations.markings}
\begin{document}

\begin{figure}[hbt!]
    \begin{center}
    \begin{tikzpicture}[scale=0.95,
                thick,
                acteur/.style={
                    circle,
                    fill=black,
                    thick,
                    inner sep=2pt,
                    minimum size=0.2cm,scale=0.65
                }
                ] 
                \node (a1) at (0,0) [acteur,label=left:\footnotesize{1}]{}; 
                \node (a2) at (1.5,0)  [acteur,label=right:\footnotesize{2}]{};           
                \node (a3) at (1.5,1.5) [acteur,label=right:\footnotesize{3}]{};     
                \node (a4) at (0,1.5) [acteur,label=left:\footnotesize{4}]{};         
                \node (a5) at (.75,3) [acteur,label=above:\footnotesize{5}]{};                
                \draw [green, decoration={markings, mark=at position 0.5 with {\arrow{>}}}, postaction={decorate}]  (a1) -- (a2); 
                \draw  [blue](a2) -- (a3); 
                \draw [green, decoration={markings, mark=at position 0.5 with {\arrow{>}}}, postaction={decorate}]  (a3) -- (a4);
                \draw  [red](a4) -- (a1);
                \draw [blue] (a4) -- (a5);
                \draw [red]  (a5) -- (a3);
               \draw (7, 1.5) node {$A(G)=
  \left[ {\begin{array}{rrrrr}
   0 & \mathrm{i} & 0 & 1 & 0 \\
   -\mathrm{i} & 0 & -1 &0 &0 \\
   0 & -1 & 0 & \mathrm{i} & 1\\
   1 & 0 & -\mathrm{i} &0 & -1\\
   0 & 0 &1 &-1 &0
  \end{array} } \right]$};
   \end{tikzpicture}

\caption{ $G, A(G)$}\label{Fd2}
          \end{center}
    \end{figure} 
\end{document}

Putting a matrix just beside a graph

2 Answers2