I am trying to make this graph

I have had several advances compared to my original question, but I don't know how to color the part blue,
This is the result that I have obtained together with the code

settings.render=8;
import three;
import solids;
import bsp;
import graph3;
size (5cm,0);
draw(unitsphere, rgb(0,0.6,0.8) + opacity(.95));
path3 xyplane = path3(scale(1) * box((-1.5,-1.5),(1,0)));
real a=1/(4sqrt(2));
real b=1/(4sqrt(2));
real long=3.3;
real y0=0.28;
real m=180atan(b/sqrt(y0y0-a*a))/pi;
real rotY=4;
real rotZ=65;
real rotXY=-10;
draw(surface(rotate(rotXY,X-Y) * rotate(rotY,Y)rotate(rotZ,Z)rotate(m,X)*xyplane),surfacepen=gray,black + opacity(1));
draw(surface(rotate(rotXY,X-Y) * rotate(rotY,Y)rotate(rotZ,Z)rotate(-m,X)*xyplane),surfacepen=lightgray,black+opacity(1));
surface cylinderSurfaceTiltedPlane(real a, real b, real z0, real y0) {
triple parametricCylinder(pair p) {
real Phi = p.x;
real Z = p.y;
real x = Z;
real y = acos(Phi)-y0;
real z = bsin(Phi);
return (x,y,z);
}
return surface(parametricCylinder, (0,-3z0/4), (2pi,13z0/20), Spline);
}
surface cF = rotate(rotXY,X-Y) * rotate(rotY,Y)rotate(rotZ,Z) cylinderSurfaceTiltedPlane(a, b, long, y0);
draw(cF,rgb(255/255,195/255,0/255));
triple f(real t) {
return (cos(t)cos(0), cos(t)sin(0), sin(t));
}
path3 circ = graph(f, 0, 2pi, operator ..);
draw(rotate(rotXY,X-Y) * rotate(75+90,Z)circ,black + 0.1pt);
draw(rotate(rotXY,X-Y) rotate(75,Z)*circ,black + 0.1pt);
triple g(real t) {
return (cos(t), sin(t),0);
}
path3 cir = graph(g, 0, 2pi, operator ..);
draw(rotate(rotXY,X-Y) * rotate(rotY,Y)rotate(rotZ,Z)cir,black + 0.1pt);
I tried to make it pretty general, since by moving the parameters each one can generate the result you want with the desired perspective. But as I mentioned, I don't know how to do the coloring I have tried to use this:

Code:
import three;
settings.render=8;
size(5cm);
//currentprojection=perspective(50,80,50);
draw(unitsphere, rgb(0,0.6,0.8) + opacity(.95));
triple A=(0.98,-0.17,0.14);
triple MAB=(0,-0.78,0.64); //mid-edge (AB)
triple B=(-0.98,-0.17,0.14);
triple MBC=(-0.89,-0.46,0); //mid-edge
triple C=(-0.98,-0.17,-0.14);
triple MAC=(0,-0.98,0.2); // mid-edge
path3 gc1=(A..MAB..B); //to avoid computation
path3 gc2=(B..(-0.93,-0.33,0.18)..MBC); // I use asymptote path3 routine
path3 gc3=(MBC..MAC..A);
// I recover the different tangents in A, B, C
// to construct a cycle-path3 of length 3.
path3 gc=point(gc1,0){dir(gc1,0)}..{dir(gc1,2)}point(gc1,2){dir(gc2,0)}
..{dir(gc2,2)}point(gc2,2){dir(gc3,0)}..{dir(gc3,2)}point(gc3,2)..cycle;
draw(surface(patch(gc)),blue);
draw(gc1^^gc2^^gc3);
//dot((gc1^^gc2^^gc3),red);
But as you can see it only covers a part, it is too laborious to calculate the points so that everything goes well, at first I thought about patching it until it comes out, but after a few hours of trying I gave up.
Original question
the cylinder must have as its center (*,-1/3,0), in this way the cylinder must be parallel to the x axis. Where the planes are tangent to the cylinder and seen in the yz-plane, we have something like this


