2

I want to draw something like this : an eye with an arc.

I started like this but I don't know how to continue

\documentclass[reqno]{amsart}
\usepackage{tikz}
\begin{document}
\begin{tikzpicture}
\draw (0,0) arc(0:-180:3);
\draw[very thick,yshift=6cm](-3,0) .. controls (-2,2) and (2,2) .. (3,0) .. controls (2,-2) and (-2,-2) .. (-3,0)--cycle;                                                                
\end{tikzpicture}
\end{document}
Vrouvrou
  • 541
  • 3
    Once again (since you already posted this question before), it could be helpful to know exactly what this drawing means and what exact part of it you're struggling with. In particular, is this meant to be a 3D drawing? And if yes, on what plane are the different parts meant to be drawn? – SebGlav Feb 10 '22 at 11:43
  • No not 3d it is an eue with an arc that's all – Vrouvrou Feb 10 '22 at 13:40
  • This seems related to this topic : https://tex.stackexchange.com/questions/94082/help-with-the-design-of-an-eye-in-tikz – Tobard Feb 11 '22 at 16:11

1 Answers1

5

OK, so here we go. Since I don't really know what you need, I'll give it a try.

an eye with an arc

\documentclass[tikz, border=3.14mm]{standalone}

\usetikzlibrary{arrows.meta}


\begin{document}
    \begin{tikzpicture}[>={Stealth[scale=2]}]
        \def\xr{5}
        \draw[fill=pink] (\xr,0) to [out=120,in=60] (-\xr,0) to [out=-60,in=-120] (\xr,0) -- cycle;
        \draw (\xr,0) to [out=down,in=down,looseness=3] (-\xr,0);
        \draw[->] (0,0) -- (2\xr,0);
        \draw[->] (0,0) -- (0,1.5\xr);
        \draw[->] (0,0) -- (-1.5\xr,-1.5\xr);


    \foreach \angle in {30,60,120,150,...,330}
        {
        \ifnum\angle=270
            \pgfmathsetmacro{\coef}{sqrt(abs(cos(60)))}%
        \else
            \pgfmathsetmacro{\coef}{sqrt(abs(cos(\angle)))}%
        \fi
        \draw[dashed] (0,0) -- (\angle:1.1*\xr*\coef);
        }
\end{tikzpicture}



\end{document}
SebGlav
  • 19,186