In a separate post, @00dani provided a nifty way of labeling points with TikZ's pin option which I'm trying to mimic.
options for labeling single point
Specifically, in a system of 1 quadratic and 1 liner equation, I want to label the 2 intersection points. The solution set for the system = (-6,3) and (-3,-3).
Presently the pointers aren't referring to the correct intersection points.
The desired graph is:
Maybe the graph is too crowded to allow for labeling the intersection points. @kissmyarmpit suggests PSTricks package to place a simple large black dot.
\documentclass[pstricks,border=12pt]{standalone}
\usepackage{pst-plot}
\usepackage{pst-eucl}
\def\f(#1){x^2+0.5}
Personally, I know very little about TiKz graphing and appreciate your most readable solution for labeling the points.
Thank you!
mwe
\usepackage{pgfplots}
\begin{document}
\begin{center}
\begin{tikzpicture}
\begin{axis}[
% width and height if axis, adjust to your liking
width=7cm,
height=6cm,
%xtick=\empty,
% remove all ticks from x-axis
%ytick=\empty, % ditto for y-axis
xlabel=$x$,
ylabel=$y$,
axis lines=center, % default is to make a box around the axis
domain=-10.5:5,
samples=100]
\addplot [red] {-2*x-9};
\addplot [blue] {2(x+4)^2-5};
%callout for intersection point
\addplot[mark=*] coordinates {(-6,3)} node[pin=150:{$(-6,3)$}]{} ;
\addplot[mark=*] coordinates {(-3,-3)} node[pin=150:{$(-3,-3)$}]{} ;
\end{axis}
\end{tikzpicture}
\end{center}
\end{document}



(-6,3)and(-3,-3)are the correct coordinates for the intersections? – Jasper Habicht Apr 17 '23 at 22:16*in the formula. See my answer. – Jasper Habicht Apr 18 '23 at 07:26