How to make the elements of the first row of this table rotate like this photo

Question

I'm trying to make this table and as you see it, the first row is rotated

So far I've done this

\begin{tabular}{|*{41}{c|}}  % repeats {c|} 18 times
\hline
\multicolumn{5}{|c}{Placeholders} & \multicolumn{2}{|c|}{Grouping} &
\multicolumn{3}{|c|}{Stacking} &
\multicolumn{2}{|c|}{Affixed} &
\multicolumn{3}{|c|}{Formation} & \multicolumn{3}{|c|}{Foundation} &
\multicolumn{3}{|c|}{Progression} &
\multicolumn{3}{|c|}{Transition} &
\multicolumn{3}{|c|}{Aggregation} &
\multicolumn{3}{|c|}{Execution} &
\multicolumn{5}{|c|}{Fixation} &
\multicolumn{3}{|c|}{Modality} &
\multicolumn{3}{|c|}{Meta Symbol} \\ \hline 
P & O & A & S & F & P & O & P & O & A & P & O & 1 & 2 & 3 & (1, 1) & (1, 2) & (2, 1) & P & O & A & P & O & A & P & O & A & P & O & A & P & O & A & Group P & Group A & P & O & A & P & O & A \\ \hline
\end{tabular}

I appreciate the help

Edit:

I managed to do this so far

\newcolumntype{R}[2]{%
    >{\adjustbox{angle=#1,lap=\width-(#2)}\bgroup}%
    c%
    <{\egroup}%
}
\newcommand*\rottttt{\multicolumn{5}{R{90}{1em}}}%
\newcommand*\rottt{\multicolumn{3}{R{90}{1em}}}%
\newcommand*\rott{\multicolumn{2}{R{90}{1em}}}%
\begin{tabular}{|*{41}{c|}}
\hline
\rottttt{Placeholders} &
\rott{Grouping} &
\rottt{Stacking} &
\rott{Affixed} &
\rottt{Formation} &
\rottt{Foundation} &
\rottt{Progression} &
\rottt{Transition} &
\rottt{Aggregation} &
\rottt{Execution} &
\rottttt{Fixation} &
\rottt{Modality} &
\rottt{Meta Symbol} \ \hline
P & O & A & S & F &
P & O &
P & O & A &
P & O &
1 & 2 & 3 &
(1, 1) & (1, 2) & (2, 1) &
P & O & A &
P & O & A &
P & O & A &
P & O & A &
P & O & A & Group P & Group A &
P & O & A &
P & O & A \ \hline
\end{tabular}

But the lines are gone and It's not fitting in the page

no the problem is all the rotating solutions are for 1 to 1 cells, what about multi column cells ? — zEn feeLo, Jun 30 '23 at 17:49

Zarko · Accepted Answer · 2023-06-30T22:24:59.723

Like this:

With tabularray, makecell and rotating package is simple:

\documentclass{article}
\usepackage[margin=25mm]{geometry}
\usepackage{rotating}   % needed
\usepackage{makecell}   % needed
\usepackage{tabularray}
\begin{document}
    \begin{table}[ht]
\begin{tblr}{hlines, vlines,
             colspec = {*{35}{Q[c,font=\small]}},
             colsep  = 3pt,
             rowsep  = 0pt,
             row{1}  = {cmd=\settowidth\rotheadsize{Placeholder}\rothead, font=\sffamily\bfseries}, % <----
             cell{2-Z}{1-Z} = {m},
            }
\SetCell[c=5]{} Placeholders

    &   &   &   &   &

    \SetCell[c=2]{} Grouping
        &   &

        \SetCell[c=3]{} Stacking 
            &   &   &
            \SetCell[c=2]{} Affixed
                &   &
                \SetCell[c=3]{} Formation
                    &   &   &
                    \SetCell[c=3]{} Foundation
                        &   &   &
                        \SetCell[c=3]{} Progression
                            &   &   &
                            \SetCell[c=3]{} Transition
                                &   &   &
                                \SetCell[c=3]{} Aggregation
                                    &   &   &
                                    \SetCell[c=3]{} Execution
                                        &   &   &
                                        \SetCell[c=5]{} Fixation
                                            &   &   &   &   \
P & O & A & S & F 
    & P & O 
        & P & O & A 
            & P & O 
                & 1 & 2 & 3 
                    & \SetCell{cmd=\settowidth\rotheadsize{(1,2)}\rothead} (1,1) 
                        & \SetCell{cmd=\settowidth\rotheadsize{(1,2)}\rothead} (1,2) 
                            & \SetCell{cmd=\settowidth\rotheadsize{(1,2)}\rothead} (2,1) 
                        & P & O & A 
                            & P & O & A 
                                & P & O & A 
                                    & P & O & A 
                                        & P & O & A & \SetCell{cmd=\settowidth\rotheadsize{Group P}\rothead}  Group P 
                                                         & \SetCell{cmd=\settowidth\rotheadsize{Group A}\rothead} Group A 
                                                         \
\end{tblr}
    \end{table}
\end{document}

@KamranAsgari, but it is centered (horizontally) ! Do you like to have vertical centered too? Well, frankly said to my opinion this ugly design of table, I will not do this. But if you insist to do this, let me know. I will look tommorow, what I can do. — Zarko, Jul 07 '23 at 21:02
because there are 3 rows, one extra on top of that , what do you think ? maybe only the first row vertically bottom and the second and third row centred ? — zEn feeLo, Jul 07 '23 at 21:11
I'm also thinking, the whole table should be rotated :( that's gonna better design — zEn feeLo, Jul 07 '23 at 21:11

F. Pantigny · Answer 2 · 2023-07-18T06:10:32.517

EDIT:

With the version 6.21 of nicematrix which provides \rotate[c]:

\documentclass{article}
\usepackage[margin=25mm]{geometry}
\usepackage{nicematrix}
\begin{document}
\begin{table}[ht]
\setlength{\tabcolsep}{1pt}
\begin{NiceTabular}{*{35}{c}}[hvlines,cell-space-limits=2pt]
\RowStyle{\rotate[c]}
\Block{1-5}{Placeholders} &   &   &   &   &

\Block{1-2}{Grouping} &   &

\Block{1-3}{Stacking} &   &   &
\Block{1-2}{Affixed} &   &
\Block{1-3}{Formation} &   &   &
\Block{1-3}{Foundation} &   &   &
\Block{1-3}{Progression} &   &   &
\Block{1-3}{Transition} &   &   &
\Block{1-3}{Aggregation} &   &   &
\Block{1-3}{Execution} &   &   &
\Block{1-5}{Fixation} &   &   &   &   \
P & O & A & S & F & P & O & P & O & A & P & O & 1 & 2 & 3 & 
\rotatec & 
\rotatec & 
\rotatec & 
P & O & A & P & O & A & P & O & A & P & O & A & P & O & A & 
\rotate[c]Group P & \rotate[c]Group A \
\end{NiceTabular}
\end{table}
\end{document}

Here is a solution with {NiceTabular} of nicematrix.

\documentclass{article}
\usepackage[margin=25mm]{geometry}
\usepackage{nicematrix}
\begin{document}
\begin{table}[ht]
\setlength{\tabcolsep}{1pt}
\begin{NiceTabular}{*{35}{c}}[hvlines,cell-space-limits=2pt]
\RowStyle{\rotate}
\Block{1-5}{Placeholders} &   &   &   &   &

\Block{1-2}{Grouping} &   &

\Block{1-3}{Stacking} &   &   &
\Block{1-2}{Affixed} &   &
\Block{1-3}{Formation} &   &   &
\Block{1-3}{Foundation} &   &   &
\Block{1-3}{Progression} &   &   &
\Block{1-3}{Transition} &   &   &
\Block{1-3}{Aggregation} &   &   &
\Block{1-3}{Execution} &   &   &
\Block{1-5}{Fixation} &   &   &   &   \
P & O & A & S & F & P & O & P & O & A & P & O & 1 & 2 & 3 & 
\rotatebox[origin=c]{90}{(1,1)} & 
\rotatebox[origin=c]{90}{(1,2)} & 
\rotatebox[origin=c]{90}{(2,1)} & 
P & O & A & P & O & A & P & O & A & P & O & A & P & O & A & 
\rotatebox[origin=c]{90}{Group P} & \rotatebox[origin=c]{90}{Group A} \
\end{NiceTabular}
\end{table}
\end{document}

You need several compilations (because nicematrix uses PGF/Tikz nodes under the hood).

If you want the elements of the first row vertically centered, you should use the key v-center of the command Block.

\documentclass{article}
\usepackage[margin=25mm]{geometry}
\usepackage{nicematrix}
\begin{document}
\begin{table}[ht]
\setlength{\tabcolsep}{1pt}
\begin{NiceTabular}{*{35}{c}}[hvlines,cell-space-limits=2pt]
\RowStyle{\rotate}
\Block[v-center]{1-5}{Placeholders} &   &   &   &   &

\Block[v-center]{1-2}{Grouping} &   &

\Block[v-center]{1-3}{Stacking} &   &   &
\Block[v-center]{1-2}{Affixed} &   &
\Block[v-center]{1-3}{Formation} &   &   &
\Block[v-center]{1-3}{Foundation} &   &   &
\Block[v-center]{1-3}{Progression} &   &   &
\Block[v-center]{1-3}{Transition} &   &   &
\Block[v-center]{1-3}{Aggregation} &   &   &
\Block[v-center]{1-3}{Execution} &   &   &
\Block[v-center]{1-5}{Fixation} &   &   &   &   \
P & O & A & S & F & P & O & P & O & A & P & O & 1 & 2 & 3 & 
\rotatebox[origin=c]{90}{(1,1)} & 
\rotatebox[origin=c]{90}{(1,2)} & 
\rotatebox[origin=c]{90}{(2,1)} & 
P & O & A & P & O & A & P & O & A & P & O & A & P & O & A & 
\rotatebox[origin=c]{90}{Group P} & \rotatebox[origin=c]{90}{Group A} \
\end{NiceTabular}
\end{table}
\end{document}

Thanks, how can I center the text in the first row ? :) – zEn feeLo Jul 07 '23 at 20:52 — zEn feeLo, Jul 07 '23 at 20:52
I have modified my answer... – F. Pantigny Jul 08 '23 at 16:19 — F. Pantigny, Jul 08 '23 at 16:19

score 1 · Answer 3 · answered Jul 02 '23 at 13:04

With tabularray and adjustbox by separating content and form as much as possible

remark: cell{2}{16-18} = {cmd=\rotatebox[origin=c]{90}} don't work.

The code

\documentclass{article}
\usepackage[margin=25mm]{geometry}
\usepackage{adjustbox}
\usepackage{tabularray}
\begin{document}
\begin{table}[ht]
  \begin{tblr}{
      hlines, vlines,
      colspec = {*{35}{Q[c,m,font=\small]}},
      stretch = 0,
      colsep  = 3pt,
      rowsep  = 2pt,
      row{1}  = {cmd=\rotatebox{90}, font=\sffamily\bfseries},
      cell{1}{1,31} = {r=1,c=5}{c},
      cell{1}{6,11} = {r=1,c=2}{c},
      cell{1}{8,13,16,19,22,25,28} = {r=1,c=3}{c},

      %cell{2}{16-18} = {cmd=\rotatebox[origin=c]{90}},
      cell{2}{34-35} = {h,cmd=\rotatebox{90}},
    }
    Placeholders&&&&&
    Grouping&&
    Stacking&&&
    Affixed&&
    Formation&&&
    Foundation&&&
    Progression&&&
    Transition&&&
    Aggregation&&&
    Execution&&&
    Fixation&&&&
    \
    %
    P & O & A & S & F
      & P & O
      & P & O & A
      & P & O
      & 1 & 2 & 3
      & \rotatebox[origin=c]{90}{(1,1)}
      & \rotatebox[origin=c]{90}{(1,2)}
      & \rotatebox[origin=c]{90}{(2,1)}
      & P & O & A
      & P & O & A
      & P & O & A
      & P & O & A
      & P & O & A & Group P & Group A
  \end{tblr}
\end{table}
\end{document}

How to make the elements of the first row of this table rotate like this photo

3 Answers3