problem with multicol and big picture

Question

The picture is too high to stay in the first column, but the remaining text spreads over the entire height of this column. The only way I've found to avoid this problem is to place an empty vbox at a certain height. This is hardly satisfactory. What's the best method?

\documentclass{scrartcl}
\usepackage{tikz}
\usepackage{multicol,lipsum}
\setlength{\columnsep}{24pt}
\setlength{\columnseprule}{0.4pt}
\begin{document}
\begin{multicols*}{2}
\section{Contruction with inversion}
Let us consider the circle $\mathcal{T}$ of center $T$ point common to the circles $\mathcal{A}$ and $\mathcal{B}$ and tangent to the line $(EF)$. It intercepts the two circles at 4 points which define two lines $\mathcal{L_A}$ and $\mathcal{L_B}$ perpendicular to the line $(AB)$.
Consider the inversion of center $T$ with respect to the circle $\mathcal{T}$. The circles $\mathcal{A}$ and $\mathcal{B}$ have as inverses the lines $\mathcal{L_A}$ and $\mathcal{L_B}$.
The orange circle passing through $T$ and tangent to the circle $\mathcal{T}$ and to the line $(EF)$ is therefore tangent to the line $(EF)$. This circle is therefore tangent to the lines $\mathcal{L_A}$ and $\mathcal{L_B}$ since $(EF)$ is tangent to the circles $\mathcal{A}$ and $\mathcal{B}$.
%\vbox to 10cm{}
\begin{tikzpicture}
    \draw (0,0)--(7,15) (0,15)--(7,0);
 \end{tikzpicture}
\lipsum[2]
 \end{multicols*}
\end{document}

Answer 1

This adds enough text to fill the first column, then uses my linked solution.

\documentclass{scrartcl}
\usepackage{tikz}
\usepackage{multicol,lipsum}
\setlength{\columnsep}{24pt}
\setlength{\columnseprule}{0.4pt}
\makeatletter
\newcommand{\split}[2]% #1 = text, #2 = insert
{\par\bgroup
  \setbox0=\vbox{\strut #1\strut}% measure height
  \sbox1{#2}% ditto
  \dimen0=\dimexpr \pagegoal-\pagetotal-\col@number\baselineskip\relax% fudge factor
  \dimen1=\pagegoal% compute height of one column
  \ifnum\col@number>1\relax
    \divide\dimen1 by \col@number
  \fi
  \advance\dimen1 by -\baselineskip% fudge factor
  \loop\ifdim\dimen0>\dimen1% space left in this column
    \advance\dimen0 by -\dimen1
  \repeat
  \dimen1=\dimexpr \ht1+\dp1+\textfloatsep\relax% space needed for insert
  \ifdim\dimen1>\dimen0
    \ifdim\ht0>\dimen0
      \setbox2=\vsplit0 to \dimen0
      \unvbox2
      \noindent\box1
      \vskip\textfloatsep
      \unvbox0
    \else% entire text will fit into column
      \unvbox0
      \vskip\textfloatsep% probably ignored
      \noindent\box1
      \vskip\textfloatsep
    \fi
  \else% insert will fit into column
    \vskip\intextsep
    \noindent\box1
    \vskip\intextsep
    \unvbox0
  \fi
\egroup\par}
\makeatother
\begin{document}
\begin{multicols*}{2}
\section{Contruction with inversion}
Let us consider the circle $\mathcal{T}$ of center $T$ point common to the circles $\mathcal{A}$ and $\mathcal{B}$ and tangent to the line $(EF)$. It intercepts the two circles at 4 points which define two lines $\mathcal{L_A}$ and $\mathcal{L_B}$ perpendicular to the line $(AB)$.
Consider the inversion of center $T$ with respect to the circle $\mathcal{T}$. The circles $\mathcal{A}$ and $\mathcal{B}$ have as inverses the lines $\mathcal{L_A}$ and $\mathcal{L_B}$.
The orange circle passing through $T$ and tangent to the circle $\mathcal{T}$ and to the line $(EF)$ is therefore tangent to the line $(EF)$. This circle is therefore tangent to the lines $\mathcal{L_A}$ and $\mathcal{L_B}$ since $(EF)$ is tangent to the circles $\mathcal{A}$ and $\mathcal{B}$.\strut
\split{\lipsum[2-3]}{\noindent\begin{tikzpicture}
    \draw (0,0)--(\columnwidth,15) (0,15)--(\columnwidth,0);
 \end{tikzpicture}}
\end{multicols*}
\end{document}

---

If you like big gaps, you can use

\split{\vfill}{\noindent\begin{tikzpicture}
    \draw (0,0)--(\columnwidth,15) (0,15)--(\columnwidth,0);
\end{tikzpicture}}