If in a command \foo is one of my arguments, e.g. #1 how can I do a \def for \foobar, i.e., define a command with bar added to #1?
Specifically I try the following
\documentclass{scrbook}
\usepackage[refpage,noprefix]{nomencl}
\makeatletter
\newcommand*{\defsym}[3][]{\def#2{%
\ifx\protect\@unexpandable@protect
#3%
\else
\nomenclature{$#3$}{#1}\gdef#2{#3}#3%
\fi} %
%\def#2FwD{#3} % <-- this does not work
}
\makeatother
\usepackage{amsmath,amsfonts,amssymb}
\defsym{\Rn}{\mathbb{R}^n}
\makenomenclature
\begin{document}
$\Rn$ will be introduced later ...
%$\RnFwD$ will be introduced later ...
\clearpage
$\Rn$ is defined as ...
\printnomenclature
\end{document}
This uses List of symbols/abbreviations and macros to automatically put a symbol (here \Rn) in the Nomenclature (List of Symbols) on its first use. This works nicely for more, but now I got the rare ocasion that I want to make a first use of symbol that should not yet be recorded in the nomenclature. To this end I want to introduce a command \xFwd for every command \x declared by \defsym.
I tried this above, but when I uncomment that line I get the error
Use of \Rn doesn't match its definition. which I think is due to the question that I posed first.