I'm using {^2K} to write the indices on the left side, but when I do so I get an unwanted space between 2 en K. Is there another way to write the "power" indices on the left side?
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\fbox{\parbox{38em}{
\textbf{text}
\textit{text}
\begin{eqnarray}
f^{(M)}(z)\underbrace{(K_1,K_2,\ldots,K_M)}_\text{operandi}= \sum\limits_{i=1}^m \sum\limits_{j_1=1}^m \sum\limits_{j_2=1}^m \ldots \sum\limits_{j_M=1}^m {^if_{j_1 j_2\ldots j_M}}{^{j_1}K_1}{^{j_2}K_2}\ldots{^{j_M}K_Me_i},
\end{eqnarray}
waarbij $z$ het argument is en
\begin{eqnarray}
K_t &=& [{^1K_t, ^2K_t,\ldots, ^mK_t}]^T \in \mathbb{R}^m, \qquad t = 1,2,\ldots,M, \nonumber \\
{^if_{j_1 j_2\ldots j_M}} &=& \frac{\partial^M{^if(z)}}{\partial^{j1}z\partial^{j2}z\ldots\partial^{jM}z},
\end{eqnarray}
}
The result that I get is this
I'd like to make the sapce there smaller, or to write {^2K_t} in another away.
PS how can I remove the unwanted space here
\!. So in this case, you could say$^2\!K$. Is that what you mean? – Jake Nov 26 '13 at 14:27$^2$Kor$^2\mathrm{K}$don't have the space. – someonr Nov 26 '13 at 14:31\begin{eqnarray} K_t &=& [{^1!K_t, ^2!K_t,\ldots, ^m!K_t}]^T \in \mathbb{R}^m, \qquad t = 1,2,\ldots,M, \end{eqnarray}
– vixero Nov 26 '13 at 14:31alignovereqnarray. See: http://texblog.net/latex-archive/maths/eqnarray-align-environment/ – Johannes_B Nov 26 '13 at 14:32fouridxpackage, especially if you ever want an index on the left of a large symbol. – Chris Chudzicki Nov 26 '13 at 14:40\sidesetif it is a large operator. – Svend Tveskæg Nov 26 '13 at 14:41