swap a label to inner corner

Question

I have below code section, the label "B" is displayed at the outside of the corner, how can we swap it to the inner corner? or any other good suggestion to label it?

\documentclass{standalone}
\usepackage{tikz}
\usetikzlibrary{positioning,fit,calc}
\begin{document}

\begin{tikzpicture}[inner sep=0mm,outer sep=0,node distance=4em,
  box/.style={draw,anchor=west,minimum width=10em,minimum height=3em},
]
  \node (A) [box] {A};
  \node (B) [below=of A.west,box,label=south west:B] {};  
\end{tikzpicture}
\end{document}

The output picture is:

enter image description here

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score 6 · Answer 1 · edited Apr 13 '17 at 12:35

An alternative to @Harish's solution (which I think is easier) is to manually set the anchor of the label node. I follow this answer and define an inside key, which causes labels to be put "inside" a node:

\usepackage{etoolbox}
\makeatletter
\tikzset{inside/.code=\preto\tikz@auto@anchor{\pgf@x-\pgf@x\pgf@y-\pgf@y}}
\makeatother

Then one can pass this key to the label operation along with other options (e.g. inner sep=1pt to give extra padding to the label node).

Code

\documentclass[border=2pt]{standalone}
\usepackage{tikz}
\usetikzlibrary{positioning,fit,calc}
\usepackage{etoolbox}
\makeatletter
\tikzset{inside/.code=\preto\tikz@auto@anchor{\pgf@x-\pgf@x\pgf@y-\pgf@y}}
\makeatother

\begin{document}

\begin{tikzpicture}[inner sep=0mm,outer sep=0,node distance=4em,
  box/.style={draw,anchor=west,minimum width=10em,minimum height=3em},
]
  \node (A) [box] {A};
  \node (B) [below=of A.west,box,label={[inside,inner sep=1pt]south west:B}] {};  
\end{tikzpicture}
\end{document}

Output

enter image description here

score 5 · Accepted Answer · answered Jan 03 '14 at 23:55

A label is supposed to exist outside a node so as to avoid confusion between the contents and label. The easiest IMO is to add an extra node for labelling.

\documentclass{standalone}
\usepackage{tikz}
\usetikzlibrary{positioning,fit,calc}
\begin{document}

\begin{tikzpicture}[inner sep=0mm,outer sep=0,node distance=4em,
  box/.style={draw,anchor=west,minimum width=10em,minimum height=3em},
]
  \node (A) [box] {A};
  \node (B) [below=of A.west,box] {}node at ($(B.south west) +(0.15,0.15)$) {B};
\end{tikzpicture}
\end{document}

enter image description here

Jesse · Answer 3 · 2014-01-04T12:46:45.080

This attempt is also an alternative solution when compared with @Harish and @Kevin's solutions (which I think is easy and simple). The first one need calc, the other needs inside/.code. This solution uses anchor and at of node position commands.

enter image description here

Code

\documentclass[border=10pt]{standalone}
\usepackage{tikz}
\usetikzlibrary{positioning,fit,calc}
\begin{document}

\begin{tikzpicture}[inner sep=0.1mm,outer sep=0,node distance=4em,
  box/.style={draw,anchor=west,minimum width=10em,minimum height=3em},
]
  \node (A) [box] {A};
  \node (B) [below=of A.west, box] {}; 
  \node     [anchor=south west, at=(B.south west)]{B};
\end{tikzpicture}
\end{document}

swap a label to inner corner

3 Answers3

Code

Output