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I'm trying to figure out how to display x^n with 0 as coefficient in the polynom divison. I'm using the polynom package for this but the following example doesn't show x^3 and x.

Minimal example

\documentclass{article}
\usepackage{polynom}
\begin{document}
\begin{center}
\polyset{style=C,div=:,vars=x}
\polylongdiv{x^4 + 0 x^3 - 45 x^2 + 0x + 324}{x - 6}
\end{center}
\end{document}

I didn't find anything in the package's manual. So is there a solution for my problem?

Philipp
  • 151
  • Welcome to TeX.SX! This will not be that easy as we would have to redefine the package polynom. Clearly, it decides for you not to display the zero terms and I guess, it should be possible to avoid this decision. But if you just need to type such an expression (with zeros) for one time, you should have a look here: http://tex.stackexchange.com/a/155609 – LaRiFaRi Jun 30 '14 at 07:41
  • 1
    Thx. This solved my problem :) – Philipp Jun 30 '14 at 09:39
  • Good to hear. Maybe, you just post your new formula as an answer here. And if no other solutions come up the next time, you can accept it as answer. – LaRiFaRi Jun 30 '14 at 10:38

1 Answers1

2

As LaRiFaRi said here's my solution:

$\tabularShortstack{crcrcrcrcrl}{
    &(x^4       &+      &0x^3       &-          &45x^2      &+          &0x         &+      &324        &): (x-6) = x^3 + 6x^2 - 9x - 54\\
-       &(x^4       &-      &6x^3       &)          &           &           &           &\\
\rl{-}  &\rl{(x^4}  &\rl{-} &\rl{6x^3.} &\rl{)}     &           &           &           &\\
    &           &       &6x^3       &-          &45x^2      &           &           &\\
    &           &-      &(6x^3      &-          &36x^2      &)          &           &\\
    &           &\rl{-} &\rl{(6x^3} &\rl{-}     &\rl{36x^2-}&\rl{.)}    &           &\\
    &           &       &           &           &-9x^2      &+          &0x         &\\
    &           &       &           &-          &(-9x^2     &+          &54x        &)\\
    &           &       &           &\rl{-}     &\rl{(-9x^2}&\rl{+}     &\rl{54x))} &\rl{)}\\
    &           &       &           &           &           &           &           &\\
    &           &       &           &           &           &           &-54x       &+      &324\\
    &           &       &           &           &           &-(         &-54x       &+      &324        &)\\
    &           &       &           &           &           &\rl{-(}    &\rl{-54x}  &\rl{+} &\rl{324}   &\rl{)}\\
    &           &       &           &           &           &           &           &       &0
}$

enter image description here

Philipp
  • 151