I am trying to draw a half sphere with several arrows on it. Each of those arrows should have a circle positioned on it, drawn in a local coordinate system of the arrow. I managed to draw the sphere and the arrows, but I cannot get the circle perspective right.
Any suggestions?
\documentclass[11pt]{article}
\usepackage{tikz}
\usepackage{tikz-3dplot}
\usepackage{verbatim}
\usepackage[active,tightpage]{preview}
\PreviewEnvironment{tikzpicture}
\setlength\PreviewBorder{5pt}%
%: isometric South West : X , South East : Y , North : Z
\tikzset{isometricXYZ/.style={x={(-0.866cm,-0.5cm)}, y={(0.866cm,-0.5cm)}, z={(0cm,1cm)}}}
%% document-wide tikz options and styles
\begin{document}
\begin{tikzpicture} [scale=4, isometricXYZ, line join=round,
opacity=.75, text opacity=1.0,%
>=latex,
inner sep=0pt,%
outer sep=2pt,%
]
\def\h{5}
\newcommand{\quadrant}[2]{
\foreach \f in {85,75,...,5}
\foreach \t in {#1}
\draw [dotted, fill=#2]
({sin(\f - \h)*cos(\t - \h)}, {sin(\f - \h)*sin(\t - \h)}, {cos(\f - \h)})
-- ({sin(\f - \h)*cos(\t + \h)}, {sin(\f - \h)*sin(\t + \h)}, {cos(\f - \h)})
-- ({sin(\f + \h)*cos(\t + \h)}, {sin(\f + \h)*sin(\t + \h)}, {cos(\f + \h)})
-- ({sin(\f + \h)*cos(\t - \h)}, {sin(\f + \h)*sin(\t - \h)}, {cos(\f + \h)})
-- cycle;
}
%Quadrants
\quadrant{130,140,...,310}{gray!2}
\quadrant{-50,-40,...,130}{gray!2}
%View arrows
\def\l{1.15}
\foreach \f in {0,10,...,90}
\foreach \t in {95}
\draw [black, ->, thick]
({\l*sin(\f)*cos(\t)},{\l*sin(\f)*sin(\t)},{\l*cos(\f)})
-- ({sin(\f)*cos(\t)},{sin(\f)*sin(\t)},{cos(\f)});
% Circles in local coordinate system of the arrows
\foreach \f in {0,10,...,90}
\foreach \t in {95}
{
\def\PosX{{\l*sin(\f)*cos(\t)}}
\def\PosY{{\l*sin(\f)*sin(\t)}}
\def\PosZ{{\l*cos(\f)}}
\def\Pos{(\PosX, \PosY, \PosZ)}
\begin{scope}[rotate around={\f:\Pos}]
\draw[->,red,thick] \Pos circle (0.07);
\end{scope}
};
\end{tikzpicture}
\end{document}
Current result. The drawn circles dont look right atm.

