TikZ rotating coordinate problem

Question

I am trying to rotate point (B0) by 90 degrees ccw around (A1) and then loop it to get (B\k) and (A\k). What am I doing wrong?

\documentclass[tikz]{standalone}
\begin{document}
\begin{tikzpicture}[scale=5]
\coordinate (A0) at (0,0);
\coordinate (B0) at (0,1);
\path[draw,blue](A0)--(B0)coordinate[pos=.382](A1);
\coordinate(B1)at([rotate around={90:(A1)}]B0);
\draw[red](A1)--(B1);
\end{tikzpicture}
\end{document}

red is what I get using

([rotate around={90:(A1)}]B0)

and green is what I would like to see.

hint--> play around with scale value – percusse Jul 22 '15 at 13:19 — percusse, Jul 22 '15 at 13:19

score 1 · Answer 1 · answered Jul 22 '15 at 11:57

1

Like this?

\documentclass[12pt]{article}
\pagestyle{empty}
\usepackage{tikz}
\begin{document}
\center
\begin{tikzpicture}[scale=5]
\coordinate (A0) at (0,0);
\node (A) at (A0) {A};
\coordinate (B) at (0,1);
    \foreach \k in {0,90,180,270}
    {
        \node (B\k) at ([rotate around={\k:(A0)}]B) {B\k};;
    }
\end{tikzpicture}
\end{document}

answered Jul 22 '15 at 11:57

Konne

624

Not exactly. The centres for rotations in a loop will be succesive A\j. But his is not the issue yet. The problem is that B1 is not where I want it to be. – Rafał Jul 22 '15 at 12:04
Shall it look like using \draw[red](A1)--([rotate around={90:(A1)}]B0); ? – Konne Jul 22 '15 at 12:10
Still what I get by ([rotate around={90:(A1)}]B0) is sth like (1,2), but I want (-.618,.382) – Rafał Jul 22 '15 at 12:25
@Konne In your example, change (0,0) by (1,0) to see the problem of your answer... – Paul Gaborit Jul 22 '15 at 15:50

Intercombats · Answer 2 · 2015-07-22T16:02:51.050

1

It seems that the source of your problem is scaling. It scales coordinates of center of rotation twice. Once when you define (A1), second for rotation (you can see this by explicit notation {90:(0,1.91)})

\begin{tikzpicture}
\tikzstyle{subj} = [circle, minimum width=0.2mm, draw,inner sep=1mm]
\coordinate (A0) at (0,0);
\coordinate (B0) at (0,5);
\path[draw,blue](A0)--(B0) coordinate[pos=.382](A1);
\coordinate(B1)at ([rotate around={90:(A1)}]B0);
\draw[red](A1)--(B1);
\node[subj] at (A0) {A0};
\node[subj] at (B1) {B1};
\node[subj] at (B0) {B0};
\node[subj] at (A1) {A1};
\end{tikzpicture}

edited Jul 22 '15 at 16:02

answered Jul 22 '15 at 15:51

Intercombats

31

Yes, you're right. B1 moves while I change scale. But I want the picture scaled. Hence there seem to be 2 solutions: change scale by adjusting A0 or do this \p trick to enable perform normal scaling. Thanks. – Rafał Jul 22 '15 at 17:29

score 0 · Answer 3 · edited Apr 13 '17 at 12:35

Ok, I got it. That question helped a lot:

Why such rotate in tikz doesn't work?

Now my code enriched with loop is like this and works perfectly:

\documentclass[tikz]{standalone}
 \usetikzlibrary{shapes.arrows,chains,positioning,intersections,decorations.text}
\usetikzlibrary{calc}
\usepackage{ifthen}
\begin{document}
%
\center
\begin{tikzpicture}[scale=15]
\coordinate (A0) at (0,0);
\coordinate (B0) at (0,1);
\draw[blue](A0)--(B0);
\foreach \k[evaluate={\ki=int(\k-1)}] in {1,...,7}
{\path(A\ki)--(B\ki)coordinate[pos=.382](A\k);
\draw[red] let \p\ki=(A\ki), \p\k=(A\k) in (\p\k)--([rotate around={90:(\p\k)}]B\ki)coordinate(B\k);
\node[draw] at (B\k){B\k};}
\end{tikzpicture}
\end{document}

TikZ rotating coordinate problem

3 Answers3