For the square brackets in both examples.
I would like to make this
$$ \quad \left[ 1+\left( { \frac { 1 }{ 140 } u }^{ 14 } \right) \right] $$
to look like this the values 0 and 1 in this (on the square brackets.)
For the square brackets in both examples.
I would like to make this
$$ \quad \left[ 1+\left( { \frac { 1 }{ 140 } u }^{ 14 } \right) \right] $$
to look like this the values 0 and 1 in this (on the square brackets.)
You can use the regular super-/subscript notation for setting "ranges" to brackets:
\documentclass{article}
\usepackage{amsmath}
\begin{document}
\begin{align*}
x &= \biggl[ \frac{t^3}{6} - \frac{t^2}{2} - 6t \biggr]^4_1 \\
x &= \left[ \frac{t^3}{6} - \frac{t^2}{2} - 6t \right]^4_1
\end{align*}
\end{document}
\documentclassand only the packages in the preamble that are directly relevant to this. Then you should have\begin{document}followed by the code snippet you have above and finally finish it with\end{document}. The idea is that people can come in and copy/paste the code you provide so that we don't have to guess what you might've done which will ultimately help you get an answer :) – JP-Ellis Feb 17 '16 at 03:24\[…\]preferable to$$? – Werner Feb 17 '16 at 15:06