how do i create a linebreak in an inline math formula?

Question

I tried to make a equation in Latex but the parentheses disappear near the edge of the page. How I put the equation in two lines?

$\left(\omega=\frac{d\theta}{dt}=\int_{0}^{\dot{\theta}}
d(\dot{\theta}) ; \omega^2=\int_{0}^{\dot{\theta}}d(\dot{\theta}^2)
\right)$ varia de 0 at\'{e} $\dot{\theta}:$

Answer 1

Judging by the screenshots you've posted, the culprit is the ill-advised use of \left( and \right) in the inline math formula. Material inside a \left( ... \right) construct is never broken across lines. Never, ever. If you need to enlarge the opening and closing parentheses of the inline formula, use \Bigl( and \Bigr) instead.

As proof, consider the following screenshot and associated LaTeX code. It shows that zero line break possibilities are available if \left( ... \right) is used in the formula. In contrast, TeX finds four such possibilities if \Bigl( ... \Bigr) is used. I leave it to you to decide which method you should be using.

\documentclass{article}
\usepackage{mathpazo} % looks like you're using a Palatino font
\setlength\textwidth{1mm} % choose an extremely narrow measure
\setlength\parindent{0pt} % just for this example
\begin{document}

\mbox{\emph{With} \texttt{\string\left} and \texttt{\string\right}: 
\textbf{zero} linebreak possibilities in the formula}


\medskip
$\left(\omega=\frac{d\theta}{dt}=
\int_0^{\dot{\theta}} d(\dot{\theta});\allowbreak 
\omega^2=\int_{0}^{\dot{\theta}}d(\dot{\theta}^2) \right)$

\bigskip
\mbox{\emph{Without} \texttt{\string\left} and \texttt{\string\right}: 
\textbf{four} [!] linebreak possibilities}

\medskip
$\Bigl(\omega=\frac{d\theta}{dt}=
\int_0^{\dot{\theta}} d(\dot{\theta});\allowbreak 
\omega^2=\int_{0}^{\dot{\theta}}d(\dot{\theta}^2) \Bigr)$

\end{document}

Answer 2

The problematic text seems to be like a parenthetical remark rather than a single formula. I'd avoid enlarged parentheses (solution A), but it's possible to get them as shown in solution B.

My preferred way would be avoiding the parentheses altogether (thanks to Paulo Cereda for help with Portuguese).

\documentclass{article}
\usepackage[T1]{fontenc}
\usepackage[utf8]{inputenc}
\usepackage[portuguese]{babel}

\usepackage[a4paper,margin=2cm]{geometry}

\usepackage{newpxtext,newpxmath}

\begin{document}

\subsection{A}

A qual pode ser integrada para ângulos de $\theta_0$ a 
$\theta$ enquanto a velocidade angular
($\omega=\frac{d\theta}{dt}=\int_{0}^{\dot{\theta}}d(\dot{\theta})$;
$\omega^2=\int_{0}^{\dot{\theta}}d(\dot{\theta}^{2})$)
varia de $0$ até $\theta$:

\subsection{B}

A qual pode ser integrada para ângulos de $\theta_0$ a 
$\theta$ enquanto a velocidade angular
$\Bigl(\omega=\frac{d\theta}{dt}=\int_{0}^{\dot{\theta}}d(\dot{\theta})$;
$\omega^2=\int_{0}^{\dot{\theta}}d(\dot{\theta}^{2})\Bigr)$
varia de $0$ até $\theta$:

\subsection{C}

A qual pode ser integrada para ângulos de $\theta_0$ a 
$\theta$ enquanto a velocidade angular, com
$\omega=\frac{d\theta}{dt}=\int_{0}^{\dot{\theta}}d(\dot{\theta})$ e
$\omega^2=\int_{0}^{\dot{\theta}}d(\dot{\theta}^{2})$,
varia de $0$ até $\theta$:

\end{document}