Using any symbol for "\limits"

Question

I want to use different symbols instead of Sigma for \sum and the like. I tried

\mathop{\Lambda}\limits^n_{i=1}

But the symbol is small compared to \sum

Then I tried the relsize package

\mathop{\mathlarger{\mathlarger{\mathlarger{\mathlarger{\Lambda}}}}}\limits^n_{i=1}

But then it throws off the baseline

Ideally I want the two to be vertically aligned.

Any help is appreciated.

EDIT: Both answers are great. But both have some scaling problems

Steven's solution is too big in display mode:

$$\sum_{i=1}^n \bigGreek{\Lambda}_{i=1}^n\foo_{i=1}^n \sum_{i=1}^n$$

egreg's solution is too small in inline mode (removed limits for clearer comparison)

Inline: $\sum \bigGreek{\Lambda} \foo \sum$

In practice, I probably will be using a combination of both. Unfortunately I can only accept one answer, and my OP was in display mode.

http://tex.stackexchange.com/questions/56765/getting-the-expectation-symbol-to-behave-like-sum-instead-of-sigma?rq=1 ? — Au101, Apr 26 '16 at 23:47

score 7 · Answer 1 · edited Apr 13 '17 at 12:35

Using my answer at How are big operators defined?, I merely substituted \Lambda instead of \maltese. While the symbols are slightly different vertical heights, one notes the limits are aligned for both the sigma and lambda.

\documentclass{article}
\usepackage{amsmath}
\usepackage{amsfonts}
\DeclareMathOperator*{\foo}{\scalerel*{\Lambda}{\sum}}
\usepackage{scalerel}
\begin{document}
\centering
\[
\sum_{k=1}^6\foo_{i=3}^{k}(f^2(i)f(k))
\]

This is inline: \(\sum_{k=1}^6\foo_{i=3}^{k}(f^2(i)f(k)) \)
\end{document}

egreg · Accepted Answer · 2018-02-04T16:52:09.933

A variation on \bigmaltese:

\documentclass{article}
\usepackage{graphicx}
\usepackage{amsmath}

\makeatletter
\newcommand{\bigGreek}[1]{%
  \DOTSB
  \mathop{% we want it to be an operator
    \mathchoice{\big@Greek\displaystyle\Large{#1}}
               {\big@Greek\textstyle\large{#1}}
               {\big@Greek\scriptstyle\normalsize{#1}}
               {\big@Greek\scriptscriptstyle\small{#1}}%
    }\slimits@
}

\newcommand{\big@Greek}[3]{%
  \vcenter{%
    \sbox\z@{$#1\sum$}%
    \dimen@=0.875\dimexpr\ht\z@+\dp\z@\relax
    #2% font size
    \hbox{\resizebox{!}{\dimen@}{$\m@th#3$}}%
  }%
  \vphantom{\sum}%
}
\makeatother

\newcommand{\bigLambda}{\bigGreek{\Lambda}}

\begin{document}
Here's in text, $\bigLambda_{i=1}^n x_i$, next in display
\[
\bigGreek{\Xi}_{i=1}^n
\bigGreek{\Sigma}_{i=1}^n
\sum_{i=1}^n \bigLambda_{i=1}^n x_i
\]
\end{document}

A better method is at https://tex.stackexchange.com/q/23432/4427 — egreg, Nov 22 '20 at 08:56

score 3 · Answer 3 · answered Apr 18 '17 at 13:37

3

The answers given assume that a big lambda operator is really what is wanted here. But couldn't the solution in this particular case be just \bigwedge?

answered Apr 18 '17 at 13:37

Sir Cornflakes

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Using any symbol for "\limits"

3 Answers3

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