\subsection{Third Isomorphism Theorem}
Let $G$ be a group, and $N\unlhd G$, $K\unlhd G$ such that $N\subseteq K\subseteq G$. Then $(G/N)/(K/N)\cong G/K$.
\subsection{Correspondence Theorem}
Let $N\unlhd G$. There exists a bijection $\phi:\{\text{all subgroups $H$ such that $N\subseteq H\subseteq G$}\}\to\{\text{subgroups of $G/N$}\}$, with $\phi(H)=H/N$.
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I refer to the above code which returns the output below. The issue I am refering to is the width of N\unlhd G, which clearly appears "wider" in the first instance, and narrower in the second instance. Is this normal?
Thanks!

